In the following examples both ex1 & ex2 variables will render an empty string with a space and not a falsy value. Whereas ex3 will be falsy and render the right side of the || operator. How can I test for empty string in the first two examples without doing an if statement?
let var1 = '';
let var2 = '';
let ex1 = `${var1} ${var2}` || "Is Falsy";
let ex2 = var1 + ' ' + var2 || "Is Falsy";
let ex3 = var1 || "Is Falsy";
i think this will work for you :
let ex2 = var1 || var2 || "Is Falsy";
Are ternary operators acceptable?
let ex1 = var1 && var2 ? `${var1} ${var2}` : "Is Falsy";
If you are okay with using conditional operators, this can be done with the help of trim() :
let var1 = '';
let var2 = '';
let ex1 = (`${var1} ${var2}`).trim()/length > 0 ? `${var1} ${var2}` : "Is Falsy";
let ex2 = (var1 + ' ' + var2).trim().length > 0 ? var1 + ' ' + var2 : "Is Falsy";
let ex3 = var1 || "Is Falsy";
console.log(ex1);
console.log(ex2);
console.log(ex3);