Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

152
Vistas
Get unique values from multiple array of objects in JS - the right way in javascript

I have these two array of objects and I want to get unique values from them! is anyone know how can I do that in JS?

let array1 = [
    { categoryName: "category 1" },
    { categoryName: "category 2" },
    { categoryName: "category 3" },
    { categoryName: "category 4" },
];

let array5 = [
    { categoryName: "category 1" },
    { categoryName: "category 2" },
    { categoryName: "category 3" },
    { categoryName: "category 4" },
    { categoryName: "category 5" },
];

let newArray = [];

for (const arr5Item of array5) {
  for (const arr1Item of array1) {
    if (arr5Item.categoryName !== arr1Item.categoryName) {
      newArray.push(arr5Item);
      break;
    } else {
      newArray.push(arr1Item);
      break;
    }
  }
}

console.log("newArray ", newArray);

about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

Array.reduce can solve your problem easily.

Step 1: Merge all of your array into one array, by three dots in javascript.

Step 2: Use Array.reduce to return your result.

let array1 = [
    { categoryName: "category 1" },
    { categoryName: "category 2" },
    { categoryName: "category 3" },
    { categoryName: "category 4" },
];

let array5 = [
    { categoryName: "category 1" },
    { categoryName: "category 2" },
    { categoryName: "category 3" },
    { categoryName: "category 4" },
    { categoryName: "category 5" },
];

const mergedArray = [...array1, ...array5];

const uniqueArray = mergedArray.reduce((acc, item) => {
   if (!acc.some(e => e.categoryName == item.categoryName)) {
      acc.push(item);
   }
   return acc;
}, []);
console.log(uniqueArray);

about 4 years ago · Juan Pablo Isaza Denunciar

0

You can easily achieve the result using Set. Using Set is efficient way

1)

let array1 = [
  { categoryName: "category 1" },
  { categoryName: "category 2" },
  { categoryName: "category 3" },
  { categoryName: "category 4" },
];

let array5 = [
  { categoryName: "category 1" },
  { categoryName: "category 2" },
  { categoryName: "category 3" },
  { categoryName: "category 4" },
  { categoryName: "category 5" },
];

const set = new Set([
  ...array1.map((o) => o.categoryName),
  ...array5.map((o) => o.categoryName),
]);

const result = [...set.keys()].map((s) => ({ categoryName: s }));
console.log(result);

2)

let array1 = [
  { categoryName: "category 1" },
  { categoryName: "category 2" },
  { categoryName: "category 3" },
  { categoryName: "category 4" },
];

let array5 = [
  { categoryName: "category 1" },
  { categoryName: "category 2" },
  { categoryName: "category 3" },
  { categoryName: "category 4" },
  { categoryName: "category 5" },
];

const set = new Set([
  ...array1.map((o) => o.categoryName),
  ...array5.map((o) => o.categoryName),
]);

const result = [];

for (let categoryName of set) result.push({ categoryName });
console.log(result);

about 4 years ago · Juan Pablo Isaza Denunciar

0

Not just one. There are a lot of methods available for this. Basically you need a looping logic.

Please find the Array.reduce implementation.

Logic

  • Create a merged array, by using spread operator.
  • Check each node of merged array in accumulator.
  • If the node from the merged array, doesnot exist in accumulator, then its unique.

Working Fiddle

let array1 = [{ categoryName: "category 1" },{ categoryName: "category 2" },{ categoryName: "category 3" },{ categoryName: "category 4" }];
let array5 = [{ categoryName: "category 1" },{ categoryName: "category 2" },{ categoryName: "category 3" },{ categoryName: "category 4" },{ categoryName: "category 5" }];
const uniqueValues = [...array1, ...array5].reduce((acc, curr) => {
  const nodeExist = acc.some(item => item.categoryName === curr.categoryName);
  const secondArrayExist = array5.some(item => item.categoryName === curr.categoryName);
  if (!nodeExist) {
    acc.push(curr);
  }
  return acc;
}, []);
console.log(uniqueValues);

If you want to get the nodes which are present in only in any one of the array, use the below logic.

Logic

  • Create a merged array.
  • Check each node in the merged array, whether its present in array1 and array5. If the node is not present in any one of array1 or array5 then this is unique node.
  • Push that node to accumulator.

Working Fiddle

let array1 = [{ categoryName: "category 1" },{ categoryName: "category 2" },{ categoryName: "category 3" },{ categoryName: "category 4" }];
let array5 = [{ categoryName: "category 1" },{ categoryName: "category 2" },{ categoryName: "category 3" },{ categoryName: "category 4" },{ categoryName: "category 5" }];
const uniqueValues = [...array1, ...array5].reduce((acc, curr) => {
  const firstArrayExist = array1.some(item => item.categoryName === curr.categoryName);
  const secondArrayExist = array5.some(item => item.categoryName === curr.categoryName);
  if (!firstArrayExist || !secondArrayExist) {
    acc.push(curr);
  }
  return acc;
}, []);
console.log(uniqueValues);

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda