Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

118
Vistas
How to transform Javascript Object based on one of the column?

I am really struggling with the Object transformation. I have an array of Object and want to transform it into Highcharts multi line chart input.

  1. For x-axis i need a object of unique dates.
  2. For Y -axis i need a series of objects, each will have equal number of points as unique dates from step 1. For a ID and date if data is available it will add that value otherwise null.

Original:

[{
    "date": "1997-09-29",
    "Count": 100,
    "ID": "AB12-R"
  },
  {
    "date": "1997-12-30",
    "Count": 104.7,
    "ID": "AB13-R"
  },
  {
    "date": "1997-12-30",
    "Count": 1192,
    "ID": "BA12-R"
  },

  {
    "date": "1998-03-30",
    "Count": 981,
    "ID": "BA12-R"
  },
  {
    "date": "1998-06-01",
    "Count": 341,
    "ID": "BA12-R"
  }
]

Output:

[
  {
    Identiy: 'AB12-R',
    data: [100, null, null, null]
  },
  {
    Identiy: 'AB13-R',
    data: [null, 104.7, null, null]
  }, {
    Identiy: 'BA12-R',
    data: [null, 1192, 981, 341]
  }
]

Explanation:

In Original i have 4 unique dates, Hence the length of data for each identity is 4. Now for each unique date i'll check if there is any entry in Original if yes i'll push it in data if not that null.

My Code:

From some help from, this is what i was trying. But this is not checking the unique dates and just creating the data object length which is equal to number of object in the Original. Here is that implementation https://jsfiddle.net/3u9penko/

const data = [{"date":"1997-09-29","Count":100,"ID":"AB12-R"},{"date":"1997-12-30","Count":104.7,"ID":"AB13-R"},{"date":"1997-12-30","Count":1192,"ID":"BA12-R"},{"date":"1998-03-30","Count":981,"ID":"BA12-R"},{"date":"1998-06-01","Count":341,"ID":"BA12-R"}];

const hcData = [];

data.forEach((d, i) => {

  const checkIfExist = hcData.find(data => data.id === d["ID"])

  if (checkIfExist) {
    checkIfExist.data[i] = d["Count"];
  } else {
    const initialData = [...Array(data.length)]
    initialData.fill(null, 0, data.length)

    initialData[i] = d["Count"];
    hcData.push({
      data: initialData,
      id: d["ID"]
    })
  }
})

console.log(hcData)

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

Create a Map of unique dates to index using a Set to get the unique dates, and then converting to a Map with the date as key, and the index as value.

Reduce the array to a Map using the ID as the key, and initializing the value with an empty array, that has the length of the dates Map size filled with null. Add the value of the current object to the array of nulls at the index of the date in the dates Map.

Convert the Map to an array of objects using Array.from().

const fn = arr => {
  // create a Map of uniqe dates with their index
  const dates = new Map(Array.from(
    new Set(arr.map(o => o.date)), 
    (v, i) => [v, i]
  ))

  return Array.from(
    arr.reduce((acc, o, i) => {
      // if an ID doesn't exist on the Map init it with an empty array of null values (counts)
      if(!acc.has(o.ID)) acc.set(o.ID, new Array(dates.size).fill(null))

      // add the current ID count to the array of counts
      acc.get(o.ID)[dates.get(o.date)] = o.Count

      return acc
    }, new Map),
    ([Identity, data]) => ({ Identity, data }) // convert to an array of objects
  )
}

const arr = [{"date":"1997-09-29","Count":100,"ID":"AB12-R"},{"date":"1997-12-30","Count":104.7,"ID":"AB13-R"},{"date":"1997-12-30","Count":1192,"ID":"BA12-R"},{"date":"1998-03-30","Count":981,"ID":"BA12-R"},{"date":"1998-06-01","Count":341,"ID":"BA12-R"}]

const result = fn(arr)

console.log(result)

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda