Could someone guide me how to find an element in an array?
I always get false for elements that exist.
Thank you.
arr = new Array;
arr.push({x: "a", y: 1});
arr.push({x: "b", y: 2});
arr.push({x: "c", y: 3});
elem = {x: "c", y: 3};
if (arr.includes(elem)){
console.log('true');
} else {
console.log('false');
}
You are looking for {x: "c", y: 3} object in arr and It will never be equal to any other object because {} !== {}.
Remember: Object are compared with reference but the primitives are checked by their value.
In your code you are checking an object reference with another reference, which is not equal so that's why it logs false.
If there are array of numbers then you should use includes as:
const arr = [10, 20, 30];
if(arr.includes(20)) console.log("true");
else console.log("false");You can use find to find the element in the array
const arr = new Array();
arr.push({ x: "a", y: 1 });
arr.push({ x: "b", y: 2 });
arr.push({ x: "c", y: 3 });
const elem = { x: "c", y: 3 };
if (arr.find((o) => o.x === elem.x && o.y === elem.y)) {
console.log("true");
} else {
console.log("false");
}since you are working with a 2d array i believe your object will be allways same for X and Y , so i suggest you to make a function like that for further use in your code
arr = new Array;
arr.push({x: "a", y: 1});
arr.push({x: "b", y: 2});
arr.push({x: "c", y: 3});
elem = {x: "c", y: 3};
console.log(findXY(arr,elem))
function findXY(arr,val){
return arr.find(each=>{
return each.x == val.x && each.y == val.y
})
}