I currently have some data in a firebase db that contains multiple members like so:
membersData: {
uid1: {
first: 'blah'
last: 'blah'
mStatus: true
}
uid2: {
first: 'blah'
last: 'blah'
mStatus: true
}
uid3: {
first: 'blah'
last: 'blah'
mStatus: false
}
}
To filter over my data I run this:
Object.keys(membersData).filter(member => membersData[member].mStatus == true)
However this only returns an array of the uid. How can I get it to return the uid but also the first, last and mStatus?
It returns the keys, because you are running from Object.keys.
Try running with Object.values to return the values you want:
Object.values(membersData).filter(member => member.mStatus == true);
You are getting only the keys with Object.keys. All the further computations are done on that array of keys. You can use a .map() again to get the items in the requested format.
You might simply use a different method like Object.values() if you are only concerned about the values and not the keys:
let membersData = {
'uid1' : {
'first': 'blah',
'last': 'blah',
'mStatus': true
},
'uid2': {
'first': 'blah',
'last': 'blah',
'mStatus': true
},
'uid3': {
'first': 'blah',
'last': 'blah',
'mStatus': false
}
}
let ans = Object.keys(membersData).filter(member => membersData[member].mStatus == true).map(x => { return { [x] : membersData[x]} } );
console.log(ans);
let ans2 = Object.values(membersData).filter(member => member.mStatus == true);
console.log(ans2);