I have one array:
const animals = ['cat', 'dog', 'cow', 'horse']
And second one:
const animalsWithNames = ['cat:mik', 'dog', 'horse:lucy']
And I need to create a function that gives me in a result a third array:
const result = ['cat', 'dog', 'horse']
So, as well I understad I have to map first array and check by function. If piece of string exist in first array's item it should be in the result one. Am I right? Please about tips or proposal solutions.
My attempt:
const checkStr = str => animalsWithNames.forEach(el => {
if (el.substring(0, str.length) === str) {
return str
}
})
const result = animals.map(el => checkStr(el))
console.log(result)
You can try using Array.prototype.filter() and Array.prototype.some() like the following way:
const animals = ['cat', 'dog', 'cow', 'horse'];
const animalsWithNames = ['cat:mik', 'dog', 'horse:lucy'];
const result = animals.filter(a => animalsWithNames.some(an => an.split(':')[0] == a));
console.log(result);Just use Array.reduce with looping through first array and checking the nodes is present in second.
const animals = ['cat', 'dog', 'cow', 'horse'];
const animalsWithNames = ['cat:mik', 'dog', 'horse:lucy'];
const result = animals.reduce((acc, curr) => {
const node = animalsWithNames.find(item => item.indexOf(curr) > -1);
if (node) {
acc.push(curr)
}
return acc;
}, []);
console.log(result);const animals = ['cat', 'dog', 'cow', 'horse']
const animalsWithNames = ['cat:mik', 'dog', 'horse:lucy']
const names = animalsWithNames.map(e => e.split(":")[0])
const result = names.filter(e => animals.includes(e))
console.log(result)