current object
const obj = {
k1: v1,
k2: v2,
x1: v3,
x2: v4,
y: {
z1: v5,
z2: v6
}
}
expected object
const obj = {
k1: v2,
k2: v1,
x1: v4,
x2: v3,
y: {
z1: v6,
z2: v5
}
}
Have tried individual swap method for each key and also tried below object assign way
const obj = {
k1: 'v1',
k2: 'v2',
x1: 'v3',
x2: 'v4',
y: {
z1: 'v5',
z2: 'v6'
}
}
Object.assign(obj, {
k1: obj.k2,
k2: obj.k1,
x1: obj.x2,
x2: obj.x1,
y: {
z1: obj.y.z2,
z2: obj.y.z1,
}
});
Object.keys(obj).forEach(
(k) =>
obj[k] === null ||
(obj[k] === undefined && delete obj[k])
);
console.log(obj)for some cases once object assign is executed undefined will come for x1 or x2 key because v3 or v4 are not mandatory. so after converting trying to remove the undefined keys from object
Expecting a optimized and better solution for it
Your solution was accession undefined keys from obj such as obj.k4 and obj.k3 also they were assigning to wrong keys aswell k3 and k4.
Your Corrected Solution
const obj = {
k1: 'v1',
k2: 'v2',
x1: 'v3',
x2: 'v4',
y: {
z1: 'v5',
z2: 'v6'
}
};
Object.assign(obj, {
k1: obj.k2,
k2: obj.k1,
x1: obj.x2,
x2: obj.x1,
y: {
z1: obj.y.z2,
z2: obj.y.z1,
}
});
console.log(obj);You can also make use of spread operator for achieving the same.
let obj = {
k1: 'v1',
k2: 'v2',
x1: 'v3',
x2: 'v4',
y: {
z1: 'v5',
z2: 'v6'
}
};
obj = {...obj, ...{
k1: obj.k2,
k2: obj.k1,
x1: obj.x2,
x2: obj.x1,
y: {
z1: obj.y.z2,
z2: obj.y.z1,
}
}}
console.log(obj);You can write a method to remove the undefined:
const clean = o => JSON.parse(JSON.stringify(o))
const obj = {
k1: 'v1',
k2: 'v2',
x1: 'v3',
x2: 'v4',
y: {
z1: 'v5',
z2: 'v6',
},
}
Object.assign(obj, {
k1: obj.k2,
k2: obj.k1,
k3: obj.k4,
k4: obj.k3,
y: {
z1: obj.v6,
z2: obj.v5,
},
})
console.log('obj:', obj)
console.log('clean object:', clean(obj))