Sample Data
var devs = [
{
name: 'ABC',
age: 26,
addr:{
country:'India',
city:'Pune',
updated:'Mar 12 2012 10:00:00 AM' //This is Date Proprty
}
},
{
name: 'ABD',
age: 25,
addr:{
country:'India',
city:'Pune',
updated:'Mar 12 2012 12:00:00 AM'
}
},
{
name: 'ABI',
age: 27,
addr:{
country:'UK',
city:'London',
updated:'Mar 13 2012 12:00:00 AM'
}
}
. ...Other
]
export interface IAddress{
id?: string;
country?:string;
city?:string;
updated?:Date;
}
let address:IAddress[];
Above is sample data. I need to implement similar case . My implementation is similar to
this.
let address= devs.filter(temp => temp.name.toLowerCase().indexOf(searchTerm.toLowerCase()) > -1).map(({addr}) => ({addr}));
Current Result:
searchTerm: AB Then in need to get Address whos name start with 'AB'
Result:
[
addr:{
country:'India',
city:'Pune',
updated:'Mar 12 2012 10:00:00 AM'
}, ///this to be remove in the final result bacause City Pune allreay available
addr:{
country:'India',
city:'Pune',
updated:'Mar 12 2012 12:00:00 AM'
},
ddr:{
country:'UK',
city:'London',
updated:'Mar 13 2012 12:00:00 AM'
}
]
Expected Result: I nee to Remove the duplicate array based on city but latest updated date
i.e only city with Pune with 'updated:'Mar 12 2012 12:00:00 AM' only should be take in the final resullt..Please some one help me to sorr and filter latest record
You can use Array.reduce to create a map of devs, using the addr.city as the key.
We'll only replace any dev for a given city if their updated property is newer than the existing one:
var devs = [ { name: 'ABC', age: 26, addr:{ country:'India', city:'Pune', updated:'Mar 12 2012 10:00:00 AM' } }, { name: 'ABD', age: 25, addr:{ country:'India', city:'Pune', updated:'Mar 12 2012 12:00:00 AM' } }, { name: 'ABI', age: 27, addr:{ country:'UK', city:'London', updated:'Mar 13 2012 12:00:00 AM' } } ];
// Update our map if
// a) the entry doesn't exist or
// b) the updated date is later than the most recent one.
const addresses = Object.values(devs.reduce((acc, cur) => {
if (!acc[cur.addr.city] ||
Date.parse(cur.addr.updated) < Date.parse(acc[cur.addr.city].addr.updated)) {
acc[cur.addr.city] = { addr: cur.addr };
}
return acc;
}, {}))
console.log('Addresses:', addresses)Array.reduce will do the trick for you.
const searchTerm = "AB";
var devs = [
{ name: 'ABC', age: 26, addr: { country: 'India', city: 'Pune', updated: 'Mar 12 2012 10:00:00' } },
{ name: 'ABD', age: 25, addr: { country: 'India', city: 'Pune', updated: 'Mar 12 2012 12:00:00' } },
{ name: 'ABI', age: 27, addr: { country: 'UK', city: 'London', updated: 'Mar 13 2012 12:00:00' } }
];
let address= devs.filter(temp => temp.name.toLowerCase().indexOf(searchTerm.toLowerCase()) > -1).reduce((acc, curr) => {
// Check if a node exist in accumulator with same city
const index = acc.findIndex((item) => item.addr.city === curr.addr.city);
if(index > -1) {
// If exist check fro the latest time
const existingTime = new Date(acc[index].addr.updated).getTime();
const newTime = new Date(curr.addr.updated).getTime();
// Replace the node with latest time
if(newTime > existingTime) {
acc[index] = curr;
}
} else {
acc.push(curr);
}
return acc;
}, []);
console.log(address);I have commented each step yo understand what we are doing
please look into my solution
var devs = [
{
name: 'ABC',
age: 26,
addr:{
country:'India',
city:'Pune',
updated:'Mar 12 2012 10:00:00 AM' //This is Date Proprty
}
},
{
name: 'ABD',
age: 25,
addr:{
country:'India',
city:'Pune',
updated:'Mar 12 2012 12:00:00 AM'
}
},
{
name: 'ABI',
age: 27,
addr:{
country:'UK',
city:'London',
updated:'Mar 13 2012 12:00:00 AM'
}
}
]
const result = devs
.map(i => i.addr) // show only addreses
.reduce((acc, curr) => {
const existed = acc.find(i => i.city === curr.city) // check if same item already exist
if(!existed) {
return [...acc, curr]; // if no exist - add current item
} else {
// Same item already stored
if(new Date(existed.updated) < new Date(curr.updated)) { // need to check which item is newest
return acc // newest already stored
} else {
const existedIndex = acc.findIndex(i => i.city === curr.city)
acc.splice(existedIndex, 1, curr)// need yo replace oldest with newwest
return acc; // return updated array
}
}
}, [])
console.log(result)