Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

105
Vistas
Best way to merge two objects on a matching key-value pair

I'm having trouble making two objects into one on a matching key.

I have two objects coming from 2 apis and there is one matching key in the objects.

I want to iterate over them and if the storeId matches in both objects, I want to merge the two together as seen in the perfectObject.

I have tried the spread operator, Object.assign, for...in loop instead of the for loop seen here, but found close to none success.

Thanks for the help!

const logistics = [{
  logisticsId: "L5E69E26D8FCAE",
  storeId: 409388,
  logisticsDate: "2020-03-12T07:19:09.000Z",
}, ];

const stores = [{
  storeId: 409388,
  ka: 0,
  country: "ru",
  name: "test",
  city: "Moscow",
  cxw: 1,
  cx: 1,
  plz: 22448,
}, ];

const perfetObject = {
  storeId: 409388,
  ka: 0,
  country: "ru",
  name: "test",
  city: "Moscow",
  cxw: 1,
  cx: 1,
  plz: 22448,
  "storeId": 409388,
  logisticsId: "L5E69E26D8FCAE",
  storeId: 409388,
  logisticsDate: "2020-03-12T07:19:09.000Z",
};
"logisticsId": "L5E69E26D8FCAE",
let d = {};
}
for (let i = 0; i < logistics.length; ++i) {
  for (let k = 0; k < stores.length; ++k) {
    if (logistics.storeId === stores.storeId) {
      d = {
        ...stores.name,
        ...stores.city,
        ...logistics.logisticsId,
      };
    }
  }
  let d = {}

  console.log(d);

about 4 years ago · Juan Pablo Isaza
2 Respuestas
Responde la pregunta

0

Leaving aside the nested for loop (there are better data structures for you to take advantage of that make this unnecessary), the easiest method would be to use Object.assign() or the spread operator, especially if the key names are guaranteed to never conflict.

const logistics = [{
  logisticsId: "L5E69E26D8FCAE",
  storeId: 409388,
  logisticsDate: "2020-03-12T07:19:09.000Z",
}, ];

const stores = [{
  storeId: 409388,
  ka: 0,
  country: "ru",
  name: "test",
  city: "Moscow",
  cxw: 1,
  cx: 1,
  plz: 22448,
}, ];

for (let i = 0; i < logistics.length; ++i) {
  for (let k = 0; k < stores.length; ++k) {
    if (logistics[i].storeId === stores[k].storeId) {
      console.log(Object.assign({}, logistics[i], stores[k]));
    }
  }
}

This assumes all store IDs are valid (e.g. have the expected store data) and all logistics elements have a valid store defined.

about 4 years ago · Juan Pablo Isaza Denunciar

0

This is a working example answer from a reddit user u/albedoa:

const storesByStoreId = stores.reduce(
  (obj, store) => {
    if (!obj.hasOwnProperty(store.storeId)) {
      obj[store.storeId] = store;
    }

    return obj;
  },
  {}
);

const perfectArray = logistics.map(logistic => ({
  ...storesByStoreId[logistic.storeId],
  ...logistic
}));

This way, it combines the two as supposed to, or returns the object itself if there is no match.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda