Why doesn't this code compile ? Unable to grasp nuances java method reference completely :(
public class TestClass {
static void println() {}
public static void main(String[] args) {
Runnable r1 = () -> System.out::println; // compilation error
Runnable r2 = () -> TestClass::println; // compilation error
Runnable r2 = () -> System.out.println("Hello World"); // This is fine !!
}
}
There's a bit of misunderstanding here, and other answers only provide final result. So here's a real explanation.
In java, there are lambdas (() -> something), and method references (Class::method). They're basically the same thing, just with different (shorter) syntax. You can mix lambdas and method references, if you'd like (lambda in a lambda, method reference in a lambda). As long as everything is a correct type, you're ok.
So System.out::println is a method reference of type Consumer<String>, cause System.out.println() takes String as argument, and returns void - that's Consumer<String>. (There is also System.out.println() that takes no arguments, in that case it'd be a Runnable)
Runnable is a bit different because it doesn't receive any argument or returns a value. Example could be List::clear.
As to why your code was a compilation error:
When declaring a Runnable as lambda, you have to receive no arguments and return void. This lambda: Runnable r1 = () -> System.out::println; doesn't match the criteria, because it does receive no arguments (() ->), but it's expression does return a type - Consumer<String> (or Runnable again), not a void. It could be a valid Runnable if you managed to return nothing, like
Runnable r1 = () -> {
Consumer<String> str1 = System.out::println; // either this
Runnable str2 = System.out::println; // or this
return; // return type - void
}
But that kinda doesn't make sense.
So you can see clearly, that () -> System.out::println() is actually a lambda that supplies Runnable or Consumer<String>, so it's type should be
Supplier<Runnable> s = () -> System.out::println; // either this
Supplier<Consumer<String>> s = () -> System.out::println; // or this
To use it directly, you'd just have to ditch the Supplier<>
Runnable s = System.out::println; // either this
Consumer<String> s = System.out::println; // or this
How about you just explain what you're trying to do, and we'll help you.
It should be a "direct" method reference, not a supplier of something represented by a method reference.
Runnable r1 = System.out::println;
Runnable r2 = TestClass::println;
Compare
Supplier<Runnable> a = () -> System.out::println;
with
Runnable b = System.out::println;
This is not how method references work. You use them like so:
Runnable r1 = System.out::println;