So I have here two different arrays.
const test = [
{ firstName: "John", lastName: "Doe" },
{ firstName: "Michael", lastName: "Sins" },
{ firstName: "Alex", lastName: "Brown" }
];
const test2 = [
{ firstName: "Lisa", lastName: "Shore" },
{ firstName: "John", lastName: "Doe" },
{ firstName: "Justin", lastName: "Park" },
];
What I want is to get the same values from the two arrays using ES6 (filter if possible) or in any way that fits to achieve the output. The result that I want to get is :
[{ firstName: "John", lastName: "Doe" }]
You can try using Array.prototype.filter() and Array.prototype.some()
const test = [
{ firstName: "John", lastName: "Doe" },
{ firstName: "Michael", lastName: "Sins" },
{ firstName: "Alex", lastName: "Brown" }
];
const test2 = [
{ firstName: "Lisa", lastName: "Shore" },
{ firstName: "John", lastName: "Doe" },
{ firstName: "Justin", lastName: "Park" },
];
const res = test.filter(t1 => test2.some(t2 =>
t1.firstName == t2.firstName
&& t1.lastName == t2.lastName
));
console.log(res);You can do:
const test = [{ firstName: 'John', lastName: 'Doe' },{ firstName: 'Michael', lastName: 'Sins' },{ firstName: 'Alex',lastName: 'Brown' }]
const test2 = [{ firstName: 'Lisa', lastName: 'Shore' },{ firstName: 'John', lastName: 'Doe' },{ firstName: 'Justin',lastName: 'Park' }]
const getFullName = ({ firstName, lastName }) => firstName + lastName
const test2Names = test2.map(getFullName)
const result = test.filter((o) => test2Names.includes(getFullName(o)))
console.log(result)Thi swill still works if you have object with properties other than firstName and lastName
const test = [
{ firstName: "John", lastName: "Doe" },
{ firstName: "Michael", lastName: "Sins" },
{ firstName: "Alex", lastName: "Brown" }
];
const test2 = [
{ firstName: "Lisa", lastName: "Shore" },
{ firstName: "John", lastName: "Doe" },
{ firstName: "Justin", lastName: "Park" },
];
const tempTest2 = test2.map(item => JSON.stringify(item));
const result = test.filter(item => tempTest2.includes(JSON.stringify(item)));
console.log(result);