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VistasSpringBoot: create object from generic type in generic mapper
I have a lot of entity extend Catalog entity and as well as have a lot of dto that extent CatalogDto
And I have a generic repository, service, and mapper as follows
My repository:
@Repository
public interface CatalogRepository<T extends Catalog> extends JpaRepository<T, Integer>{
}
My service:
@Service
@Transactional
public class CatalogServiceImpl<T extends Catalog,Dto extends CatalogDto>{
private final Logger log = LoggerFactory.getLogger(CatalogServiceImpl.class);
private final CatalogRepository<T> repository;
private CatalogMapper<T,Dto> catalogMapper=new CatalogMapper<T,Dto>() {};
public CatalogServiceImpl(CatalogRepository<T> repository) {
this.repository = repository;
}
}
My Mapper:
public abstract class CatalogMapper<T extends Catalog,Dto extends CatalogDto> implements Rapper<T,Dto> {
@Override
public Dto entityToDto(T entity) {
return null;
}
@Override
public T dtoToEntity(Dto dto) {
return null;
}
}
I want to create an object from T in dtoToEntity method and an object from Dto in entityToDto method in CatalogMapper class
·
Santiago Trujillo
1 Respuestas
Responde la pregunta0
I think that these two methods should be abstract because every mapper probably works in different ways. Anyway you can provide a base implementation like this
public T dtoToEntity(Dto dto) throws InstantiationException, IllegalAccessException {
T entity = (T) ((Class)((ParameterizedType)this.getClass().
getGenericSuperclass()).getActualTypeArguments()[0]).newInstance();
BeanUtils.copyProperties(dto, entity);
return entity;
}
public Dto entityToDto(T entity) throws InstantiationException, IllegalAccessException {
Dto dto = (Dto) ((Class)((ParameterizedType)this.getClass().
getGenericSuperclass()).getActualTypeArguments()[1]).newInstance();
BeanUtils.copyProperties(entity, dto);
return dto;
}
Using ParameterizedType of the generic class you can create a new instance and then execute a simple copyProperties
·
Santiago Trujillo
Denunciar
Responde la pregunta