I am trying to order the array by most valued, from lowest to highest, but those with 0 rating are ordered after the highest valued, and then from highest to lowest by price
const product = [
{mostValued:5, price: 5},
{mostValued:0, price: 14},
{mostValued:0, price: 58},
{mostValued:3, price: 33},
{mostValued:0, price: 25},
{mostValued:4, price: 47},
]
// code
product.sort((a, b) =>
a.mostValued == b.mostValued
? b.price - a.price
: a.mostValued - b.mostValued
);
Those with 0 stars should be sorted after, highest to lowest by price, so the expected output would be
[
{mostValued:3, price: 33},
{mostValued:4, price: 47},
{mostValued:5, price: 5},
{mostValued:0, price: 58},
{mostValued:0, price: 25},
{mostValued:0, price: 14}
];
Easiest way would be to coalesce 0s (and other falsy values?) to Infinity:
product.sort((a, b) =>
(a.mostValued || Infinity) - (b.mostValued || Infinity) ||
b.price - a.price
);
Alternatively, specifically give those with mostValued == 0 a priority:
product.sort((a, b) =>
(a.mostValued == 0) - (b.mostValued == 0) ||
a.mostValued - b.mostValued ||
b.price - a.price
);