Necesito extraer la propiedad del supplier de matrices anidadas. ¿Hay una manera mejor y más simple de hacer esto? Mostrarlo solo una vez si tiene duplicados
La salida esperada debería ser como:
['Moscow', 'USA'] const oldData = [ { "uid": "AA1", "members": [ { "id": 123, "createdTs": "2018-11-07T04:55:00.000+00:00", "modifiedTs": "2022-03-17T23:29:06.000+00:00", "uid": "d@yahoo.com", "name": "Dayanara", "active": true, "lastLogin": "2020-10-28T03:22:22.000+00:00", "supplier": "Moscow" }, { "id": 456, "createdTs": "2018-10-28T22:42:57.000+00:00", "modifiedTs": "2020-06-01T05:01:11.000+00:00", "uid": "j@yahoo.com", "name": "John Jones", "active": true, "lastLogin": "2020-06-01T05:00:35.000+00:00", "supplier": null }, { "id": 789, "createdTs": "2022-01-28T05:21:37.000+00:00", "modifiedTs": "2022-02-04T06:24:54.000+00:00", "uid": "g@gmail.com", "name": "Gasmund", "active": true, "lastLogin": null, "supplier": "" } ] }, { "uid": "AA2", "members": [ { "id": 10112, "createdTs": "2022-07-07T09:51:14.000+00:00", "modifiedTs": "2022-07-07T09:51:14.000+00:00", "uid": "aa@yahoo.com", "name": "deqwd", "active": true, "lastLogin": null, "supplier": "USA" }, { "id": 101123, "createdTs": "2022-07-07T09:51:14.000+00:00", "modifiedTs": "2022-07-07T09:51:14.000+00:00", "uid": "aa33@yahoo.com", "name": "fewfewffwef", "active": true, "lastLogin": null, "supplier": "USA" } ] } ] const newData = oldData.flatMap((groupUsers) => ( groupUsers.members.map(({ supplier }) => ({ supplier: supplier })) )); console.log(newData)Un doble Array.flatMap ayudará.
Si tiene duplicados y espera una lista única como salida, puede usar Set
Primero flatMap para generar una lista de miembros, segundo flatMap para generar la lista de proveedores y un Set para generar la lista única a partir de esto.
const oldData = [ { uid: "AA1", members: [ { id: 123, createdTs: "2018-11-07T04:55:00.000+00:00", modifiedTs: "2022-03-17T23:29:06.000+00:00", uid: "d@yahoo.com", name: "Dayanara", active: true, lastLogin: "2020-10-28T03:22:22.000+00:00", supplier: "Moscow" }, { id: 456, createdTs: "2018-10-28T22:42:57.000+00:00", modifiedTs: "2020-06-01T05:01:11.000+00:00", uid: "j@yahoo.com", name: "John Jones", active: true, lastLogin: "2020-06-01T05:00:35.000+00:00", supplier: null }, { id: 789, createdTs: "2022-01-28T05:21:37.000+00:00", modifiedTs: "2022-02-04T06:24:54.000+00:00", uid: "g@gmail.com", name: "Gasmund", active: true, lastLogin: null, supplier: "" }, ], }, { uid: "AA2", members: [ { id: 10112, createdTs: "2022-07-07T09:51:14.000+00:00", modifiedTs: "2022-07-07T09:51:14.000+00:00", uid: "aa@yahoo.com", name: "deqwd", active: true, lastLogin: null, supplier: "USA" }, ], }, ]; const newData = oldData .flatMap(({ members }) => members) .flatMap(({ supplier }) => (supplier ? supplier : [])); const uniqueSet = Array.from(new Set(newData)); console.log(newData); console.log(uniqueSet);Puede usar filter para excluir las cadenas vacías, flatMap para recopilar el resto de los valores y Set para obtener valores únicos:
const oldData = [{"members": [{"supplier": "Moscow"},{"supplier": null},{"supplier": ""}]},{"members": [{"supplier": "USA"},{"supplier": "USA"}]}]; const newData = Array.from(new Set( oldData.flatMap(({members}) => members.map(({supplier}) => supplier).filter(Boolean) ) )); console.log(newData);Enfoque alternativo con Array.prototype.reduce :
const newData = Array.from(new Set(oldData .reduce((p, c) => p.concat(c.members.filter(m => !!m.supplier)) , []) .reduce((p, c) => p.concat(c.supplier), []) ));