I have an object array with below structure and I need to get first object's property names alone from this array and not values. My result should only have ["Name" , "Account", "Status"].
I tried below lines of code but the result was not as expected. I am getting the result along with index 0. Can someone guide me here to achieve the result.
tempVar= [
{
"Name" : "A1",
"Account" : "Dom",
"Status" : "A"
},
{
"Name" : "A5",
"IntAccount" : "Int",
"Status" : "A"
},
{
"Name" : "A2",
"LclAccount" : "Lcl",
"Status" : "A"
},
{
"Name" : "A4",
"UnknownAccount" : "UA",
"Status" : "A"
}
];
let propNames: Array<any> = [];
tempVar= tempVar.splice(0,1);
for (let el of tempVar)
{
propNames.push(Object.keys(el))
}
console.log(propNames);
You're overcomplicating it.
To get the first element, index tempVar with square brackets: tempVar[0].
Then, to get the keys, just call Object.keys() on it:
const propNames = Object.keys(tempVar[0]);
Try the following lines of code:
let propNames: Array<any> = [];
tempVar= tempVar.splice(0,1);
for (let key in tempVar)
{
propNames.push(key)
}
console.log(propNames);
Try this.
let propNames: Array<any> = [];
for (const key of Object.keys(tempVar[0])) {
propNames.push(key)
}
console.log(propNames);