In my case, the search should go through the first [1] elements of nested arrays.
I added a loop through the array elements from the answer, but I can't add the found arrays to the array.
function massivs() {
let array = [['a', 'mango', 'b','c'], ['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']];
let comp = ['apple', 'mango'];
let ans = [];
for (let i = 0; i < array.length; i++) {
for (el of array[i]) {
if (comp.every(y => el.includes(y))) {
ans.push(el);
}
}
}
console.log(ans);
}
massivs();[ 'applemango', 'mangoapple' ]
Expected Result [['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']]
You could do it with just one line of code:
const array = [['a', 'mango', 'b','c'], ['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']];
const comp = ['apple', 'mango'];
const result = array.filter(x => comp.every(y => x.some(z => z.includes(y))));
console.log(result);Replace:
ans.push(el)
With:
ans.push(array[i])
for of iterates the items of your array, so it's only pushing the element of the array that is included in your search values, push the whole array if found in search and break the loop
function massivs() {
let array = [['a', 'mango', 'b','c'], ['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']];
let comp = ['apple', 'mango'];
let ans = [];
for (let i = 0; i < array.length; i++) {
for (el of array[i]) {
if (comp.every(y => el.includes(y))) {
ans.push(array[i]);
break;
}
}
}
console.log(ans);
}
massivs();