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Iterate through an array of objects Nodejs

Need some help with this, been stuck for hours.

Trying to iterate through an array of objects in node to grab one of the key's value and perform a regex function.

I keep getting undefined reading errors, the latest one is

Cannot read properties of undefined (reading 'split')

The array is created by calling toArray() on a MongoDB collection find function:

"ups": [
  {
    "_id": "61b5ef3a8bec102408f5289e",
    "article_code": "4325832",
    "order_number": "",
    "status": "shipped",
    "tt_url": "https://www.ups.com/track?loc=en_US&tracknum=999&requester=ST/trackdetails",
    "unique_id": ""
  },
  {
    "_id": "61b5ef3a8bec102408f528b4",
    "article_code": "6242665",
    "order_number": "",
    "status": "shipped",
    "tt_url": "https://www.ups.com/track?loc=en_US&tracknum=999&requester=ST/trackdetails",
    "unique_id": ""
  },
  {
    "_id": "61b5ef3a8bec102408f528ef",
    "article_code": "3610890",
    "order_number": "",
    "status": "shipped",
    "tt_url": "https://www.ups.com/track?loc=en_US&tracknum=999&requester=ST/trackdetails",
    "unique_id": ""
  }
]

Here's my code attempt:

for(let i = 0; i < ups.length; i++) {       
    var ups_tt = i['tt_url'];
    var unique_id = i['unique_id'];
        
    var spl = ups_tt.split(/tracknum=(.*)/)[1];
    ups_tt = spl.split("&")[0];
}

Any help would be appreciated.

about 4 years ago · Santiago Gelvez
3 Respuestas
Responde la pregunta

0

so, in your example, i is just a number, so if you try to get a key of a number, then you will get undefined

> let i = 1;
undefined
> i["test"]
undefined

what you should do is reference the array ups with the index:

 for(let i = 0; i < ups.length; i++){
       
        var ups_tt = ups[i].tt_url;
        var unique_id = ups[i].unique_id;
        
        var spl = ups_tt.split(/tracknum=(.*)/)[1];
        ups_tt = spl.split("&")[0];
about 4 years ago · Santiago Gelvez Denunciar

0

Try this way:

let y = {
  "ups": [
    {
      "_id": "61b5ef3a8bec102408f5289e",
      "article_code": "4325832",
      "order_number": "",
      "status": "shipped",
      "tt_url": "https://www.ups.com/track?loc=en_US&tracknum=999&requester=ST/trackdetails",
      "unique_id": ""
    }, {
      "_id": "61b5ef3a8bec102408f528b4",
      "article_code": "6242665",
      "order_number": "",
      "status": "shipped",
      "tt_url": "https://www.ups.com/track?loc=en_US&tracknum=999&requester=ST/trackdetails",
      "unique_id": ""
    }, {
      "_id": "61b5ef3a8bec102408f528ef",
      "article_code": "3610890",
      "order_number": "",
      "status": "shipped",
      "tt_url": "https://www.ups.com/track?loc=en_US&tracknum=999&requester=ST/trackdetails",
      "unique_id": ""
    }
  ]
}
    
y.ups.forEach(element => {
  console.log(element)
});
about 4 years ago · Santiago Gelvez Denunciar

0

since the url is simple enough, you can just directly split it by "&", no need to use regex

so:

ups_tt = ups_tt.split('&')[2];
var spl = "&" + ups_tt;
about 4 years ago · Santiago Gelvez Denunciar
Responde la pregunta
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