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How can I write each line output in a file in bash?

This is part of my script:

num=`wc -l /tmp/list.txt | awk '{sum += $1} END {print sum}'`
for i in $(seq $num)
do
    touch /tmp/pages/$i.txt
done

#OR:

#awk '{system("touch /tmp/pages/"NR".txt")}' /tmp/list.txt
i=1
for line in $(cat list.txt)
do
    #for (( i = 1; i <= num; i++ )) 
    #do
    wget $line --no-check-certificate -O /tmp/pages/$i.txt
    i= i+1
    #done
done

How can I assign the output of each line in list.txt to my i variable?

For example:

line one > 1.txt

line two > 2.txt

And so on...

over 4 years ago · Santiago Trujillo

2 Respuestas

Responde la pregunta

0

With awk:

awk '{print > NR".txt"}' list.txt

over 4 years ago · Santiago Trujillo Denunciar

Responde la pregunta

Encuentra empleos remotos

Accepted Answer · 2022-04-21T18:04:33.974Z

i=1
while read line
do
    echo "$line" > /tmp/pages/$i.txt
    let i=i+1
done < list.txt

0

222

How can I write each line output in a file in bash?

2 Respuestas

0

0

Encuentra empleos remotos

Andres GPT