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How could i select a specific characters in an array at JavaScript

Can anyone help at this exercise:

Create a function named extractPassword which takes an array of characters (which includes some trash characters) and returns a string with only valid characters (a - z, A - Z, 0 - 9).

Here's an example :

extractPassword(['a', '-', '~', '1', 'a', '/']); // should return the string 'a1a'
extractPassword(['~', 'A', '7', '/', 'C']); // should return the string 'A7C'

I have done until here :

var extractPassword = function() {
  for (i = 0; i < extractPassword.length; i++) {
    var output = "";
    switch (extractPassword[i]) {
      case '-':
      case '~':
      case '/':
        break;
      default:
        output = output + extractPassword[i];
    }
    return output;
  }
};
about 4 years ago · Santiago Trujillo
3 Respuestas
Responde la pregunta

0

You can achieve this by using String.match() method with the help of RegEx.

Explanation of Regex /[a-zA-Z0-9]/ig :

[ : beginning of character group
a-z : any lowercase letter
A-Z : any uppercase letter
0-9 : any digit
] : end of character group
i : ignore case sensitivity 
g : check for all occurrence in a provided string

Live Demo :

function extractPassword(arr) {
    return arr.join().match(/[a-zA-Z0-9]/ig);
}

const res = extractPassword(['a', '-', '~', '1', 'a', '/']);

console.log(res.join(''));

Update : As author wants to do this with a plain JS without RegEx.

const str = [];

function extractPassword(arr) {
  const arrStr = arr.join('');
  for (var i = 0; i < arrStr.length; i++) {
    var word = arrStr.charCodeAt(i);
    if ((word > 47 && word < 58) || (word > 64 && word < 91) || (word > 96 && word < 123)) {
      str.push(arr[i])
    }
  }
}

extractPassword(['a', '-', '~', '1', 'a', '/']);

console.log(str.join(''));

about 4 years ago · Santiago Trujillo Denunciar

0

You can use regular expression [a-z0-9] means any English letter or number and g as a global flag and i as a case-insensitive.

const extractPassword = (str) => {
  return str.join('').match(/[a-z0-9]/gi).join()
}

console.log(extractPassword(['a', '-', '~', '1', 'a', '/']));
console.log(extractPassword(['~', 'A', '7', '/', 'C']))

about 4 years ago · Santiago Trujillo Denunciar

0

const extractPassword = (str) => {
  return str.join('').match(/[a-z0-9]/gi)
}

console.log(extractPassword(['a', '-', '~', '1', 'a', '/']).toString().replace(/,/g, ''));
console.log(extractPassword(['~', 'A', '7', '/', 'C']).toString().replace(/,/g, ''))

about 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
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