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Why does "this" change when passing a function as a call back?

I have these 2 objects:

var Foo = function () {
    this.name = 'foo';
};

Foo.prototype.sayName = function () {
    console.log(this.name);
};
var Bar = function () {
    this.cb = null;
};

Bar.prototype.setCb = function (cb) {
    this.cb = cb;
};

Bar.prototype.callCb = function () {
    this.cb();
};

And I have this result:

var foo = new Foo();
var bar = new Bar();

foo.sayName();  // "foo"
bar.setCb(foo.sayName);
bar.callCb();   // undefined

This happens because when we call foo.sayName inside Bar, this is pointing to the Bar object. Can someone explain what's happening here?

I also noticed that I can circumvent this by instead passing in an anonymous function bar.setCb(function() {foo.sayName();});. Are there other/better ways around this problem?

about 4 years ago · Juan Pablo Isaza
1 Respuestas
Responde la pregunta

0

This is the part of Javascript that most throws people coming from another language.

Basically, the this pointer is set at the time of the call. When you pull a function off an object, you just get the function, not the context in which it came from (the object it came from). This is unlike for example Python with its bound method objects.

In fact, if you did something like:

let sayName = foo.sayName
sayName()

that would also throw with an "undefined" exception, since calling it that way you lose which object you're calling the method on.

So how do you work around this? There's a couple of options, both of which involve capturing that context.

The first you can do, as the comment suggested, would be to use an arrow function:

bar.setCb(() => foo.sayName())

This "captures" the object to call the function on.

Another option would be to use the Function.bind function:

bar.setCb(foo.sayName.bind(foo))

This creates a new function instance that has it's this pointer set to foo.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
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