Here is an example of my array:
const database = [
{ name: item1, errors: true },
{ name: item2, factors: { rank: 1 } },
{ name: item3, factors: { rank: 2 } },
{ name: item2, errors: true },
];
Here is what I want:
const sorted_database = [
{ name: item3, factors: { rank: 2 } },
{ name: item2, factors: { rank: 1 } },
{ name: item1, errors: true },
{ name: item2, errors: true },
];
While this part of the post might not be necessary, to clarify, I want the array to be sorted with the rank descending and if it's undefined to remain in some random order below. I do however, need to keep all of the data. I have tried just using sort, and got an error for undefined property. I then tried making two different sets, but for some reason they rarely matched each other. Looking for an elegant solution someone perhaps knows to this that I haven't yet learned.
You could look for factors first and then sort by rank.
const
database = [{ name: 'item1', errors: true }, { name: 'item2', factors: { rank: 1 } }, { name: 'item3', factors: { rank: 2 } }, { name: 'item2', errors: true }];
database.sort((a, b) =>
!a.factors - !b.factors ||
b.factors?.rank - a.factors?.rank
);
console.log(database);.as-console-wrapper { max-height: 100% !important; top: 0; }