I have this string '2020-10-20' Can i somehow get those numbers separately like this:
const [year, month, day] = '2020-10-20'.match(/\d\d\d\d/ what should i write there?)
Or any better approach exist?
You can split the string using a delimiter as follows
const [year, month, day] = '2020-10-20'.split("-")
then you would have year=2020 etc.
Using regex you can do something like this:
console.log('2020-10-20'.match(/\d+/g))If you want to use Array.prototype.split, you can do something like this
console.log('2020-10-20'.split("-"))I'll add a little bit to the above solutions. If you want to get those values as number then use the map method.
const dateString = "2020-10-12";
const [year, month, date] = dateString.split("-").map(Number);
console.log(year, month, date);By the way, If you want to learn how to do that with regex, then here's how:
const dateString1 = "2020-10-10";
const dateString2 = "2020/10/10";
const dateString3 = "2020_10_10";
const pattern = /(\d{4}).(\d{2}).(\d{2})/;
/*
* \d - matches digits 0 - 9
* \d{4} - matches any 4 digits. e.g., 1234, 4587 ...
* \d{2} - matches any 2 digits.
* . - matches anything except new line ("\n"). For the
* separator.
* (anything-here) - anything inside () is called a capture
* group.
* and will be available in the result
* */
/*
* console.log(pattern.exec(dateString2))
* returns [ "2020/10/10", "2020", "10", "10" ]
* now we need to slice the arrary from index 1 to 3
* and we get [ "2020", "10", "10" ]
* */
function parseDate(dateString) {
// For invalid dateString we'll throw an error
if(!pattern.test(dateString))
throw new Error("Invalid date string");
return pattern.exec(dateString).slice(1).map(Number);
}
console.log(parseDate(dateString1))
console.log(parseDate(dateString2))
console.log(parseDate(dateString3))