Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

116
Vistas
RegExp.prototype.exec() can loop forever

Steps to reproduce:

  • Open the MDN docs page: https://developer.mozilla.org/docs/Web/JavaScript/Reference/Global_Objects/RegExp/exec.
  • Open 'Developer Tools' and switch to the Console tab.
  • Replace foo* with .* on the docs page and click 'Run' button.

This will result in an infinite loop. How do I prevent this from happening? In my Node application, the user can specify .* as the pattern and it hangs. I do not think doing a string-match and preventing this specific regex pattern would help as there might be many other patterns that will result in an infinite loop.

Source code (in case the content of the MDN page changes):

const regex1 = RegExp('.*', 'g');
const str1 = 'text';
let array1;

while ((array1 = regex1.exec(str1)) !== null) {
  console.log(array1.index);
}
almost 4 years ago · Santiago Trujillo
2 Respuestas
Responde la pregunta

0

You could add a check that the lastIndex property of the regex has changed, and if it hasn't (indicating a zero-length match, which would then loop infinitely), break out of the loop:

const regex1 = RegExp('.*', 'g');
const str1 = 'text';
let array1;
let lastIndex = 0;

while ((array1 = regex1.exec(str1)) !== null) {
  console.log(array1);
  if (regex1.lastIndex == lastIndex) break;
  lastIndex = regex1.lastIndex;
}

Note you can put the test before doing anything with the result of the exec, depending on whether you want to capture the zero-length match or not.

almost 4 years ago · Santiago Trujillo Denunciar

0

All patterns that can match an empty string exhibit this behaviour - see Regex that can match empty string is breaking the javascript regex engine or Zero-Length regexes and infinite matches?.

The simple solution would be to just use matchAll instead testing for some complicated loop condition yourself:

const regex = /.*/g;
const str = 'text';
for (const match of str.matchAll(regex)) {
  console.log(match.index, match[0]);
}

Alternatively, using str.match(regex) instead of regex.exec(str) would also help.

almost 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda