I'm trying to schedule my script to run at two different times and then keep running in the background waiting for the next time that the conditions are met again.
So far I am not able to do it because after that one condition is met this scripts exits automatically:
function schedule {
while :
do
hour=$(date +"%H")
minute=$(date +"%M")
if [[ "$hour" = "02" && "$minute" = "31" ]]; then
# run some script
exec /home/gfx/Desktop/myscript.sh
wait
schedule
elif [[ "$hour" = "02" && "$minute" = "32" ]]; then
# run some script
exec /home/gfx/Desktop/myscript.sh
wait
schedule
fi
done
}
schedule
The script that I execute is the following :
$cat myscript.sh
echo "this a message"
Any idea or comment are welcome, thanks!
When you do:
exec some program
something else
if the exec works, then the something else will never happen because the script is replaced by what you exec'd
Maybe instead of:
exec /home/gfx/Desktop/myscript.sh
wait
schedule
you want:
/home/gfx/Desktop/myscript.sh &
wait
# schedule -- don't make a fork bomb
As noted in the comments, & + wait is kind of silly, you probably want:
/home/gfx/Desktop/myscript.sh &
# wait
# schedule
or:
/home/gfx/Desktop/myscript.sh
# wait
# schedule
depending on whether or not you want myscript in the background.
ALSO you should put a sleep in the loop, (maybe sleep(59)) to keep it from looping like a banshee.
You begin to understand the appeal of cron I think (at least for things you don't want to interact with your terminal session).
Crontabs are best place to put these things.
Edit crontab using
$ crontab -e
Add following lines to the files
31 2 * * * /home/gfx/Desktop/myscript.sh
And save crontab file. Your script will be executed every day 2:31 am