given the following structure:

.
├── a1
│   ├── q
│   ├── w
│   └── e
├── a2
│   ├── q
│   ├── e
│   └── s

I want a nested for-loop & find $ if-statement that has to work in the linux.

The expected output is the structures of sub-directory after checking if it contains a specific string in declared array.

I want something like this code:

declare -a folderlist=("a1", "a2")
declare -a checklist=("w", "s")

for folder in "${folderlist[@]}";
do
  subfolders=$(ls ./$folder);
  for subfolder in "${subfolders[@]}";

    do 
      if [ $d == "w" -o $d == "s" ]; 
         then echo ./$folder/$subfolder;
      fi;
    done;

done;

I wonder this part above:

do 
  if [ $d == "w" -o $d == "s" ]; 
     then echo ./$folder/$subfolder;
  fi;
done;

• How can I change [ $d == "w" -o $d == "s" ] part to something like if [ $d is in checklist ] ?

Expected Ouput:

./a1/w/
./a2/s/