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VistasHow to select data from a row that has a value
I am creating a social network that has an explore page. I want to show a post text or an image in two separate divs. The way it shows now isn't what I want.
It shows text and an image in the same div and if there is no image it shows a blank square where the image is supposed to be. It's an explore page so I want the post text and image to show up randomly and in separate divs and if there's nothing in the image div, it'll just show the text and vice versa.
$explore_image = $con->prepare('SELECT body, image FROM posts ORDER BY RAND()');
$explore_image->execute();
$explore_image->store_result();
$explore_image->bind_result($body, $image);
// output data of each row
while ($explore_image->fetch()) {
echo '<div id="rcorners2">';
echo "$body <img src='" . $image . "' id='explore_post_pic'></br><br><br><br>
</div><br>" ;
}
UPDATE!!! -
This code only shows one image and one div
$explore_image = $con->prepare('SELECT body, image FROM posts ORDER BY RAND()');
$explore_image->execute();
//$explore_image->store_result();
//$explore_image->bind_result($body, $image);
$explore_image_result = $explore_image->get_result();
while ($row = $explore_image_result->fetch_assoc()) {
//$id = $row['id'];
$body = $row['body'];
//$added_by = $row['added_by'];
//$date_time = $row['date_added'];
$image = $row['image'];
}
// output data of each row
if (!empty($image)) {
# code...
echo '<div id="rcorners2">';
echo "<img src='" . $image . "' id='explore_post_pic'></br><br><br><br>
</div><br>" ;
}
·
Santiago Trujillo
2 Respuestas
Responde la pregunta0
Remove $explore_image->store_result.
See the documentation. And do not forget to close both the prepared statement and the connection (in this order) after finished.
Based on your initial code:
$explore_image = $con->prepare('SELECT body, image FROM posts ORDER BY RAND()');
$explore_image->execute();
// $explore_image->store_result();
$explore_image->bind_result($body, $image);
// output data of each row
while ($explore_image->fetch())
{
if (!empty($image))
{
echo '<div id="rcorners2">';
echo "$body <img src='$image' id='explore_post_pic'></br><br><br><br></div><br>";
}
}
$explore_image -> close();
$con -> close();
·
Santiago Trujillo
Denunciar
0
<?php
$explore_image = $con->prepare('SELECT body, image FROM posts ORDER BY RAND()');
$explore_image->execute();
$explore_image->store_result();
$explore_image->bind_result($body, $image);
// output data of each row
while ($explore_image->fetch()) {
if($image!=''){
$newImage="<img src='".$image."' id='explore_post_pic'>";
}
else{
$newImage="";
}
echo '<div id="rcorners2">'.$body.'</div>';
echo '<div id="rcorners2">'.$newImage.'</div>';
}
?>
·
Santiago Trujillo
Denunciar
Responde la pregunta