I am trying to get the lat & lon properties from city object, but I get a Typescript error
Tha JSON schema is like this
{"_id":"vflv511vfsvsv51","name:"dallas","weather":{"coord":{ "lon":"-96.7836","lat": "32.7668"}}}
so normally to access them we should write something like this city.weather.lon
Error
[09:52:31] File change detected. Starting incremental compilation...
src/cities/cities.service.ts:130:30 - error TS2339: Property 'city' does not exist on type 'Mixed'.
130 const lat = city.weather.coord.lat;
~~~~~
src/cities/cities.service.ts:131:30 - error TS2339: Property 'city' does not exist on type 'Mixed'.
131 const lon = city.weather.coord.lon;
~~~~~
[09:52:32] Found 2 errors. Watching for file changes.
cities.service.ts
async GetCityWeather(cityName) {
const city = await this.cityModel.findOne({ name: cityName });
if (!city) {
this.getCityLastWeather(cityName);
}
const lat = city.weather.coord.lat;
const lon = city.weather.coord.lon;
const last7DaysWeather = this.getCityLastXDaysWeather(lat, lon);
...
}
city.model.ts
import * as mongoose from 'mongoose';
export const CitySchema = new mongoose.Schema({
name: {
type: String,
required: true,
unique: true,
index: true,
},
weather: mongoose.SchemaTypes.Mixed,
});
export interface City {
id: mongoose.Schema.Types.ObjectId;
name: string;
weather: mongoose.Schema.Types.Mixed;
}
It seems like a typescript problem instead of mongoose (Although I find it strange that weather is not defined as any in ts ), you can try this:
city.weather['coord']['lon']
Reference: error TS2339: Property 'x' does not exist on type 'Y'
city name may likely return null if not found. To guard against that, i suggest you make the city all lower and also trim spaces to make the search more accurate.
const city = await this.cityModel.findOne({ name: cityName.toLowerCase().trim() });
//save city name in db also as name.toLowerCase().trim()
if (!city) {
this.getCityLastWeather(cityName);
}
const lat = city.weather.coord.lat;
const lon = city.weather.coord.lon;
const last7DaysWeather = this.getCityLastXDaysWeather(lat, lon);
...
}