We have a mongodb document as given below, and we configured text index on messageTopic, messageTopicQuestion and answer fields, if i search with a text string then I expect only matched embedded records in the results not the entire document.
For example in below document if i search with word "private", then results should only return the first embedded document not both the records. How to retrieve only matched embedded documents and exclude unmatched ones.
{
"_id": ObjectId("586e8efdde81e56032000084"),
"messageTopic": "My Private",
"messageText": [{
"messageTopicQuestion": "agent private",
"answer": "agent private",
"_id": ObjectId("586e8efdde81e56032000085"),
"keywords": ["private"]
}, {
"messageTopicQuestion": "Greetings Checking",
"answer": "Heloo I am good What about u",
"_id": ObjectId("586fc80ccced739407000f4e"),
"keywords": ["Hi-Good", "Heloo"]
}],
"__v": 3
}
I am using below script
db.getCollection('messagetemplates').aggregate([{
$match: {
$text: {$search: 'private'},
visible: 'PUB'
}
},{ $sort: { score: { $meta: "textScore" } } }])
Appreciate help. Thanks.
I believe the question is a variation of this problem How to get a specific embedded document inside a MongoDB collection? The issue is how to get the single embedded document and exclude the rest. My suggestion is to use db.collection.find() instead of aggregation. Something in that sense
db.collection.find({ 'messageText.keyword': 'private' }, {'messageText.$': 1});
, as indicated by the answer above.
messageText.keyword can be replaced with whichever field you want to be searched.
I can confirm that the scenario works on my database.