I had a huge registration table with 112 fields. For a particular search I want to compare 17 fields & assign colors to variable say 'clrSelected'. My code is :
reg = Regisration.objects.filter('some condition').order_by("name")
for r in reg:
if r.name=='abc': clrSelected='#fff'
if r.type=='1': clrSelected='#000'
if r.appl=='10': clrSelected='#c1ff51'
if r.code=='': clrSelected='#60c5f7'
if r.qlty=='first': clrSelected='#f99334'
...
...
there will be only one if condition, which need to be colored. Which means the field(from the dictionary) to be compared will change based on the user selection. I want to access the field name from a dictionary like this
flds = {'1':'name', '2':'type', '3':'appl', '4':'code', '5':'qlty',...}
And use it something like this
if r.flds['1']=='abc': clrSelected='#fff'
How could i use the fields as above. I am using django 1.4 & python 2.7
Just to answer the question, you could use getattr:
if getattr(r, flds['1']) == 'abc': clrSelected = '#fff'
However, I am pretty sure that you could go with a different kind of implementation in this case which doesn't require using a dict like this.
I would suggest using a three tuple list: (fieldName, value, color)
some_list = [('name', 'abc', '#fff'), ('type', '1', '#000'), ...]
And, then use this list to determine the color:
for fieldName, value, color in some_list:
if getattr(r, fieldName) == value:
clrSelected = color
Looking at your implementation, it seems the color will be based on the last if condition which matches. If that is the case, you could create some_list in reverse order and break on the first matching condition.