I am actually stucked with a PHP Regex because I have to test different types of numbers.
I want to check if the first 2 numbers are in my array, but it can be possible that the first 0 is replaced by international numbers (+33 for France).
I don't have any idea how to test my following different types :
+33 (0)6
+33(0)6
+33.6
(+33).6
(+33)6
06
+33 (0)7
+33(0)7
+33.7
(+33).7
(+33)7
07
Any tips to do that ? Thanks
EDIT :
I tried this but not working wit parentesis :
^
(?:(?:\+|00)33|0) #indicatif
\s*[6-7] #first number (from 1 to 9)
(?:[\s.-]*\d{2}){4} #End of the phone number
$
Try with:
$pattern = '/^(\+33( ?\(0\)|\.)|\(\+33\)\.?|0)[67][0-9]+$/';
$my_number = "+33.678910";
if(preg_match($pattern, $my_number)) // do something
If the number of digits has to be fixed, you may replace the last + with the number (or a range of numbers) that must follows the initial 6 (or 7).
For example:
/^(\+33( ?\(0\)|\.)|\(\+33\)\.?|0)[67][0-9]{5}$/
/^(\+33( ?\(0\)|\.)|\(\+33\)\.?|0)[67][0-9]{5,7}$/
The first regex means that the initial 6 (or 7) has to be followed exactly by 5 digits. The second is from 5 up to 7.