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VistasPandas rank by multiple columns
I am trying to rank a pandas data frame based on two columns. I can rank it based on one column, but how can to rank it based on two columns? 'SaleCount', then 'TotalRevenue'?
import pandas as pd
df = pd.DataFrame({'TotalRevenue':[300,9000,1000,750,500,2000,0,600,50,500],
'Date':['2016-12-02' for i in range(10)],
'SaleCount':[10,100,30,35,20,100,0,30,2,20],
'shops':['S3','S2','S1','S5','S4','S8','S6','S7','S9','S10']})
df['Rank'] = df.SaleCount.rank(method='dense',ascending = False).astype(int)
#df['Rank'] = df.TotalRevenue.rank(method='dense',ascending = False).astype(int)
df.sort_values(['Rank'], inplace=True)
print(df)
current output:
Date SaleCount TotalRevenue shops Rank
1 2016-12-02 100 9000 S2 1
5 2016-12-06 100 2000 S8 1
3 2016-12-04 35 750 S5 2
2 2016-12-03 30 1000 S1 3
7 2016-12-08 30 600 S7 3
9 2016-12-10 20 500 S10 4
4 2016-12-05 20 500 S4 4
0 2016-12-01 10 300 S3 5
8 2016-12-09 2 50 S9 6
6 2016-12-07 0 0 S6 7
I'm trying to generate an output like this:
Date SaleCount TotalRevenue shops Rank
1 2016-12-02 100 9000 S2 1
5 2016-12-02 100 2000 S8 2
3 2016-12-02 35 750 S5 3
2 2016-12-02 30 1000 S1 4
7 2016-12-02 30 600 S7 5
9 2016-12-02 20 500 S10 6
4 2016-12-02 20 500 S4 6
0 2016-12-02 10 300 S3 7
8 2016-12-02 2 50 S9 8
6 2016-12-02 0 0 S6 9
3 Respuestas
Responde la pregunta0
The generic way to do that is to group the desired fiels in a tuple, whatever the types.
df["Rank"] = df[["SaleCount","TotalRevenue"]].apply(tuple,axis=1)\
.rank(method='dense',ascending=False).astype(int)
df.sort_values("Rank")
TotalRevenue Date SaleCount shops Rank
1 9000 2016-12-02 100 S2 1
5 2000 2016-12-02 100 S8 2
3 750 2016-12-02 35 S5 3
2 1000 2016-12-02 30 S1 4
7 600 2016-12-02 30 S7 5
4 500 2016-12-02 20 S4 6
9 500 2016-12-02 20 S10 6
0 300 2016-12-02 10 S3 7
8 50 2016-12-02 2 S9 8
6 0 2016-12-02 0 S6 9
0
pd.factorize will generate unique values for each unique element of a iterable. We only need to sort in the order we'd like, then factorize. In order to do multiple columns, we convert the sorted result to tuples.
cols = ['SaleCount', 'TotalRevenue']
tups = df[cols].sort_values(cols, ascending=False).apply(tuple, 1)
f, i = pd.factorize(tups)
factorized = pd.Series(f + 1, tups.index)
df.assign(Rank=factorized)
Date SaleCount TotalRevenue shops Rank
1 2016-12-02 100 9000 S2 1
5 2016-12-02 100 2000 S8 2
3 2016-12-02 35 750 S5 3
2 2016-12-02 30 1000 S1 4
7 2016-12-02 30 600 S7 5
4 2016-12-02 20 500 S4 6
9 2016-12-02 20 500 S10 6
0 2016-12-02 10 300 S3 7
8 2016-12-02 2 50 S9 8
6 2016-12-02 0 0 S6 9
0
Another way would be to type-cast both the columns of interest to str and combine them by concatenating them. Convert these back to numerical values so that they could be differentiated based on their magnitude.
In method=dense, ranks of duplicated values would remain unchanged. (Here: 6)
Since you want to rank these in their descending order, specifying ascending=False in Series.rank() would let you achieve the desired result.
col1 = df["SaleCount"].astype(str)
col2 = df["TotalRevenue"].astype(str)
df['Rank'] = (col1+col2).astype(int).rank(method='dense', ascending=False).astype(int)
df.sort_values('Rank')
