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Make Dictionary with only keys?

I need to make a dictionnary containing only keys.

I cannot use d.append() as it is not a list, neither setdefault as it needs 2 arguments: a key and a value.

It should work as the following:

d = {}

add "a":

d = {"a"}

add "b":

d = {"a", "b")

add "c" ...

#Final result is

d = {"a", "b", "c"}

What is the code I need to get this result? Or is it another solution? Such as making a list.

l = ["a", "b", "c"] # and transform it into a dictionnary: d = {"a", "b", "c"} ?

over 4 years ago · Santiago Trujillo

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Answer 1 · 2022-05-27T14:42:22.076Z

A dict with only keys is called a set.

Start with an empty set instead of a dictionary.

d = set()
d.add('a')
d.add('b')
d.add('c')

You can also create a set via a {} expression:

d = { 'a', 'b', 'c' }

Or using a list:

d = set(['a', 'b', 'c'])

Answer 2 · 2022-05-27T14:42:22.098Z

That should do it:

l = ["a", "b", "c"]

d = {k:None for k in l}

As @Rahul says in the comments, d = {"a", "b", "c"} is not a valid dictionary definition since it is lacking the values. You need to have values assigned to keys for a dictionary to exist and if you are lacking the values you can just assign None and update it later.

Answer 3 · 2022-05-27T14:42:22.110Z

You need a set not a dictionary,

l = ["a", "b", "c"]
d = set(l)

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Make Dictionary with only keys?

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