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jetpack compose pass parameter to viewModel

how can we pass parameter to viewModel in jetpack compose?

this is my composable

@Composable
fun UsersList() {
  val myViewModel: MyViewModel = viewModel("db2name") // pass param like this
}

this is viewModel

class MyViewModel(private val dbname) : ViewModel() {
    private val users: MutableLiveData<List<User>> by lazy {
        MutableLiveData<List<User>>().also {
            loadUsers()
        }
    }

    fun getUsers(): LiveData<List<User>> {
        return users
    }

    private fun loadUsers() {
        // Do an asynchronous operation to fetch users.
    }
}
over 4 years ago · Hanz Gallego
4 Respuestas
Responde la pregunta

0

Here's some Jetpack Compose/Kotlin-specific syntax for implementing the same:

ui/settings/SettingsViewModel.kt

class SettingsViewModel(
    private val settingsRepository: SettingsRepository
) : ViewModel() {
    /* Your implementation */
}

class SettingsViewModelFactory(
    private val settingsRepository: SettingsRepository
) : ViewModelProvider.Factory {

    override fun <T : ViewModel> create( modelClass: Class<T> ): T {
        if( modelClass.isAssignableFrom( SettingsViewModel::class.java ) ) {
            @Suppress( "UNCHECKED_CAST" )
            return SettingsViewModel( settingsRepository ) as T
        }
        throw IllegalArgumentException( "Unknown ViewModel Class" )
    }    

}

Then:

MainActivity.kt


/* dataStore by preferencesDataStore */

class MainActivity : ComponentActivity() {
    private lateinit var settingsRepository: SettingsRepository
    
    // Here we instantiate our ViewModel leveraging delegates and
    // a trailing lambda
    private val settingsViewModel by viewModels<SettingsViewModel> {
        SettingsViewModelFactory(
            settingsRepository
        )
    }

    /* onCreate -> setContent -> etc */
}
over 4 years ago · Hanz Gallego Denunciar

0

As it was mentioned by @Secret Keeper you need to create factory.

If your ViewModel has dependencies, viewModel() takes an optional ViewModelProvider.Factory as a parameter.

class MyViewModelFactory(
    private val dbname: String
) : ViewModelProvider.Factory {
    @Suppress("UNCHECKED_CAST")
    override fun <T : ViewModel> create(modelClass: Class<T>): T {
        if (modelClass.isAssignableFrom(MyViewModel::class.java)) {
            return MyViewModel(dbname) as T
        }
        throw IllegalArgumentException("Unknown ViewModel class")
    }
}

To create your viewModel you will pass optional parameter. Inside your Composable you can do something like this.

val viewModel: MyViewModel = viewModel(
factory = MyViewModelFactory(
    dbname = "myDbName"
)
over 4 years ago · Hanz Gallego Denunciar

0

you need to create a factory to pass dynamic parameter to ViewModel like this:

class MyViewModelFactory(private val dbname: String) :
    ViewModelProvider.NewInstanceFactory() {
    override fun <T : ViewModel?> create(modelClass: Class<T>): T = MyViewModel(dbname) as T
}

then use your factory like this in composable functions:

@Composable
fun UsersList() {
    val myViewModel: MyViewModel =
        viewModel(factory = MyViewModelFactory("db2name")) // pass param like this
}

and now you have access to dbname parameter in your ViewModel:

class MyViewModel(private val dbname) : ViewModel() {
    // ...rest of the viewModel logics here
}
over 4 years ago · Hanz Gallego Denunciar

0

Usually there is no common case where you need to do this. In android MVVM viewmodels get their data from repositories through dependency injection.

Here is the official documentation to the recommended android architecture: https://developer.android.com/jetpack/guide#recommended-app-arch

over 4 years ago · Hanz Gallego Denunciar
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