0
201
VistasModelChoiceField does not show ForeignKey choices
I want to show a dropdown in Django Form where the dropdown items are specified in another model in another app. Here's what I mean:
title/models.py
TITLE_CHOICES = (
('MR', 'Mr'),
('MS', 'Ms'),
('MISS', 'Miss'),
('MRS', 'Mrs'),
('MX', 'Mx'),
)
class Title(models.Model):
title_name = models.CharField(max_length=10, choices=TITLE_CHOICES)
def __str__(self):
return self.title_name
user/models.py
class User(models.Model):
...
user_title = models.ForeignKey('title.Title', on_delete=models.CASCADE)
...
user/forms.py
class SignupForm(forms.ModelForm):
user_title = forms.ModelChoiceField(queryset=Title.objects.all())
class Meta:
model = User
fields = '__all__'
def signup(self, request, user): #this is to override the **allauth** signup form
user.user_title = self.cleaned_data['title_name']
...
...
user.save()
With the above code, the dropdown field renders properly; however, it is empty.
Any ideas or suggestions are greatly appreciated.
Thanks.
3 Respuestas
Responde la pregunta0
Please change your user_title field to this and Try this.
user_title = forms.ModelChoiceField(queryset=Title.objects.all(), widget=forms.Select(attrs={'class': 'form-control'}))
0
If you are going to create all of the choices in TITLE_CHOICES you declared, I would just make a fixture and load it to database.
I would change the model a bit: title.models
def Title(models.Model):
title_name = models.CharField(max_length=10)
title = models.CharField(max_length=10)
def __str__(self):
return self.title_name
then make a json file: title/fixtures/titles.json
[
{
"model": "title.Title",
"pk": 1,
"fields": {
"title_name": "MR",
"title" : "Mr"
}
},
{
"model": "title.Title",
"pk": 2,
"fields": {
"title_name": "MS",
"title" : "Ms"
}
},
...
]
Then load this json file to database by python manage.py loaddata titles command. This will automatically create all instances in json file to database.
Note that you have to save the file in a folder named fixtures otherwise it returns error.
Now while creating the user you will get the Title ForeignKey will show the title_name in options list instead of the title.
0
user_title = forms.ModelChoiceField(queryset=Title.objects.all(), flat=True)