Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

276
Vistas
Java - Stream - Collect every N elements

I am trying to learn java - stream. I am able to do simple iteration / filter / map / collection etc.

When I was kind of trying to collect every 3 elements and print as shown here in this example, [collect every 3 elements and print and so on...]

    List<String> list = Arrays.asList("a","b","c","d","e","f","g","h","i","j");

    int count=0;
    String append="";
    for(String l: list){
        if(count>2){
            System.out.println(append);
            System.out.println("-------------------");
            append="";
            count=0;
        }
        append = append + l;
        count++;
    }
    System.out.println(append);

output:

abc
-------------------
def
-------------------
ghi
-------------------
j

I am not getting any clue how to do this using stream. Should i implement my own collector to achieve this?

about 4 years ago · Santiago Trujillo
3 Respuestas
Responde la pregunta

0

You can actually use an IntStream to simulate your list's pagination.

List<String> list = Arrays.asList("a","b","c","d","e","f","g","h","i","j");

int pageSize = 3;

IntStream.range(0, (list.size() + pageSize - 1) / pageSize)
        .mapToObj(i -> list.subList(i * pageSize, Math.min(pageSize * (i + 1), list.size())))
        .forEach(System.out::println);

which outputs:

[a, b, c]
[d, e, f]
[g, h, i]
[j]

If you want to generate Strings, you can use String.join since you are dealing with a List<String> directly:

.mapToObj(i -> String.join("", list.subList(i * pageSize, Math.min(pageSize * (i + 1), list.size()))))
about 4 years ago · Santiago Trujillo Denunciar

0

If you have Guava in your project, you can use Iterables.partition method:

import com.google.common.collect.Iterables;
import com.google.common.collect.Streams;
...

Stream<List<String>> stream = Streams.stream(Iterables.partition(list, 3));
about 4 years ago · Santiago Trujillo Denunciar

0

You can create your own Collector. The easiest way is to call Collector.of().

Since your use case requires values to be processed in order, here is an implementation that simply doesn't support parallel processing.

public static Collector<String, List<List<String>>, List<List<String>>> blockCollector(int blockSize) {
    return Collector.of(
            ArrayList<List<String>>::new,
            (list, value) -> {
                List<String> block = (list.isEmpty() ? null : list.get(list.size() - 1));
                if (block == null || block.size() == blockSize)
                    list.add(block = new ArrayList<>(blockSize));
                block.add(value);
            },
            (r1, r2) -> { throw new UnsupportedOperationException("Parallel processing not supported"); }
    );
}

Test

List<String> input = Arrays.asList("a","b","c","d","e","f","g","h","i","j");
List<List<String>> output = input.stream().collect(blockCollector(3));
output.forEach(System.out::println);

Output

[a, b, c]
[d, e, f]
[g, h, i]
[j]
about 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda