Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

341
Vistas
URLDecoder is converting '+' into space

I have a hash key in one of my query params which can have + char with other special chars. The issue is when this URL is getting decoded URLDecoder converts + char into space. Is there a way we can enforce URLDecoder not to convert '+' into space.

about 4 years ago · Santiago Trujillo
3 Respuestas
Responde la pregunta

0

Do this on your string before decoding:

String plusEncoded = yourString.replaceAll("\\+", "%2b")

The decoder will then show + where it should've been

about 4 years ago · Santiago Trujillo Denunciar

0

According to HTML URL Encoding Reference:

URLs cannot contain spaces. URL encoding normally replaces a space with a plus (+) sign or with %20.

and + sign itself must be encoded with %2B. So if you want to pass your hash as a GET parameter in URL, you should replace plus signs with %2B in your hash. Do not replace every + in the entire URL because you might ruin other string parameters which suppose to contain spaces.

about 4 years ago · Santiago Trujillo Denunciar

0

There is a bug reference similar to this issue, and it's closed as "not an issue". Here I quote what the Assignee had told:

The Java API documentation at https://docs.oracle.com/javase/8/docs/api/java/net/URL.html clearly states that "The URLEncoder and URLDecoder classes can also be used, but only for HTML form encoding, which is not the same as the encoding scheme defined in RFC2396." . This means that it is not meant for URL encoding and will cause issues with spaces and plus signs in the path. Using URL or URI classes to construct the url will give expected results.

URL url = new URL(input);
System.out.println(url.toString()); //outputs http://www.example.com/some+thing

Reference: https://bugs.openjdk.java.net/browse/JDK-8179507

about 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda