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Return custom object from Spring Data with Native Query

My question is based on another post. How can I achieve the same with a native query? Native queries do not allow JPQL thus do not allow new instances either.

My POJO.

class Coordinates {

    private final BigDecimal latitude
    private final BigDecimal longitude

    ...
}

My database table contains coordinates for cities perimeter, so there are three columns: city_name, latitude, longitude. Each city contains lots (really, LOTS) of perimeter coordinates that will be used to build a shadow area in Google Maps.

I intend to build a simple native query on that table that should return a list of coordinates.

about 4 years ago · Santiago Trujillo
3 Respuestas
Responde la pregunta

0

Found the answer on another post. Basically I used SqlResultSetMapping along with ConstructorResult (no other way worked out) with a special attention to a comment on the accepted answer of the mentioned post: you need to add the @NamedNativeQuery annotation to the entity of the used interface AND prepend the entity's name with a . otherwise it won't work.

Example:

@Entity
@Table(name = "grupo_setorial")
@SqlResultSetMapping(
        name = "mapeamentoDeQuadrantes",
        classes = {
                @ConstructorResult(
                        targetClass = Coordenada.class,
                        columns = {
                                @ColumnResult(name = "latitude"),
                                @ColumnResult(name = "longitude")
                        }
                )
        }
)
@NamedNativeQuery(
        name = "GrupoCensitario.obterPerimetroDosSetores",
        query = "SELECT latitude as latitude, longitude as longitude FROM coordenadas where id_setor IN (:setores)",
        resultSetMapping = "mapeamentoDeQuadrantes"
)
public class GrupoCensitario {
about 4 years ago · Santiago Trujillo Denunciar

0

This is https://jira.spring.io/browse/DATAJPA-980 and Here is a project that demonstrates the issue.

@Query(value = "SELECT name AS name, age AS age FROM Person", nativeQuery = true)
List<PersonSummary> findAllProjectedNativeQuery();

It is fixed in the Spring Data JPA 2.0 GA (Kay) release which comes with Hibernate 5.2.11.

The issue is also fixed for Spring Data 1.10.12 (Ingalls) and 1.11.8 (Hopper) but will need to be run on Hibernate 5.2.11 to work.

about 4 years ago · Santiago Trujillo Denunciar

0

You will have to use sql result set mapping which is part of JPA.

about 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
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