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Read Console input on spring boot with tomcat

Is it possible to read console input just before the embedded tomcat on the spring boot starts? The supposedly application flow is, request username and password from the user, and that will be used to be able to start the application. It works when using the java -jar command, the problem is when I close the console(SSH on linux) the process stops. I tried searching about it and found out that the process is tied to the console, so I tried using nohup, the problem is I cannot request for console input when using that. Is there any other way?

about 4 years ago · Santiago Trujillo
3 Respuestas
Responde la pregunta

0

I think this can help you.

public static void main(String[] args) {

    Scanner scanner = new Scanner(System.in);

    //  prompt for the user's name
    System.out.print("Enter your name: ");

    // get their input as a String
    String username = scanner.next();

    System.out.println(username);

    SpringApplication.run(Application.class, args);
}
about 4 years ago · Santiago Trujillo Denunciar

0

Get username and password in shell script before executing your java program and pass those as argument to your application.

#!/bin/bash
# Ask login details
read -p 'user: ' uservar
read -sp 'password: ' passvar
echo

Now you have user and password you can run java command with nohup and pass user password as jvm properties. You can also pass user and password as program arguments as suggested in other answer.

Like nohup java -jar abc.jar -Duser=$user -Dpassword=$password

And fetch these properties using

 String user = System.getProperty("String");
 String password = System.getProperty("password");
about 4 years ago · Santiago Trujillo Denunciar

0

You can use nohup to start the jar with the parameters, they just won't be prompted for them on new lines in the terminal. The User could add them as parameters when starting the jar. See details below.

Example:

Main Class

public static void main(String[] args) {
        String username = args[0];
        String password = args[1];
        if(username.equals("admin") && password.equals("password")) {
            SpringApplication.run(NohupApplication.class, args);
        } else {
            System.out.println("You are not authorized to start this application.");
        }
    }

With Invalid Credentials

Command

nohup java -jar example.jar user password

nohup.out

You are not authorized to start this application.

With Valid Credentials

Command

nohup java -jar example.jar admin password

nohup.out

  .   ____          _            __ _ _
 /\\ / ___'_ __ _ _(_)_ __  __ _ \ \ \ \
( ( )\___ | '_ | '_| | '_ \/ _` | \ \ \ \
 \\/  ___)| |_)| | | | | || (_| |  ) ) ) )
  '  |____| .__|_| |_|_| |_\__, | / / / /
 =========|_|==============|___/=/_/_/_/
 :: Spring Boot ::        (v1.5.2.RELEASE)
about 4 years ago · Santiago Trujillo Denunciar
Responde la pregunta
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