In my Spring MVC controller I have a method like this:
public String myMethod(@RequestParam(defaultValue="0") int param) { ... }
When I pass a string as value of my param I'm obviously getting a NumberFormatException:
Failed to convert value of type 'java.lang.String' to required type 'int'; nested exception is java.lang.NumberFormatException: For input string: "test"
That's clear...
So I'm trying to find a way to redirect user to a default page when this error is occurring. Is there a common way to achieve this?
At the moment I'm thinking about using a String in place of an int to map my param, check if this is parsable to int and then switch to the appropriate logic, but this seems a workaround, not a solution...
Is there a more elegant way to handle this problem and keep the correct type binding for my param?
Please have a look into the @Valid annotation. Hope this helps. This annotation helps in adding more validations for the request parameter.
I finally solved adding a CustomNumberEditor like this:
@InitBinder
public void registerNumbersBinder(WebDataBinder binder) {
binder.registerCustomEditor(Integer.class, new CustomNumberEditor(Integer.class, true){
@Override
public void setAsText(String text) throws IllegalArgumentException {
try{
super.setAsText(text);
}catch (IllegalArgumentException ex){
setValue(0);
}
}
});
}
In this scenario, you need to handle "MethodArgumentTypeMismatchException" you can do that using @ControllerAdvice