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Vistaslaravel-5.4 - error :Creating default object from empty value
I want to store image path in database. My Controller code undervendor\laravel\framework\src\Illuminate\Foundation\Auth\RegistersUsers.php follows:
public function register(Request $request)
{
$this->validator($request->all())->validate();
if($request->hasFile('image')) {
$image_name = $request->file('image')->getClientOriginalName();
$image_path = $request->file('image')->store('public');
$user->image = Storage::url($image_name);
$user->save();
}
event(new Registered($user = $this->create($request->all())));
// $this->guard()->login($user); disable autologin for new users
return $this->registered($request, $user)
?: redirect($this->redirectPath());
}
I am getting the following error: ErrorException in RegistersUsers.php line 40: Creating default object from empty value 
.
The image is getting saved in public folder but not able to save image path in the user table database. schema of user table
Schema::create('users', function (Blueprint $table) {
$table->increments('user_id');
$table->string('name');
$table->string('image');
$table->rememberToken();
$table->timestamps();
how to proceed to store the image path in the user table in database
2 Respuestas
Responde la pregunta0
you haven't initialized the variable $user so in the controller and before using it you've to add $user = new User; assuming that you already have use App\User;
or $user = new \App\User; if you don't.
Update
if you're trying to update an existing user record you've to initialize the $user variable by selecting based on it's primary key which should be sent in the request and then doing the initialization like:
$user_id = $request->input('user_id');
$user = User::find($user_id);
0
Use the simple way below:
$user = User::where('id', '=', $id)->first(); // where id is method param from url or request object
$user->save();
This is also easier when updating multiple tables where the ids in the sub-tables have foreign keys and need to be explicitly defined in the update process.
Also $user = User::find($id); normally work where the $id is the primary key of that object table