I am trying to find the minimum, maximum and average value in a number array:
I have the following code below:
$number = array(15,20,100,10,25,30);
for ($i=0; $i<count($number); $i++){
//Find maximum number by max function.
if ($number[$i] == max($number)){
//Print maximum number.
$max = $number[$i];
}
//Find minimum number by min function.
elseif ($number[$i] == min($number)) {
//Print minimum number.
$min = $number[$i];
}
//Find the average
else ($number[$i] == avg($number)){
//Print average number
$avg =$number[$i];
}
}
echo "min value is $min <br/>";
echo "max value is $max <br/>";
echo "average value is $avg </br>";
It seems to be giving me a syntax error on the average part. Please kindly help.
Your for loop is counterproductive here. You're already using almost all the built-in functions you need to get the values you want, but with the for loop, you're using them many more times than necessary. All you need is:
$max = max($number);
$min = min($number);
$avg = array_sum($number) / count($number);
In PHP, there's no inherent avg() function, but you can get the average easily. Sum up the total as you loop through:
$total = $total + $number[$i];
then divide by the number of values:
$avg = $total / count($number);