How could i sort e.g an array like this one:
[
'<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
'<@289037609274048513> is level **7,07** _(14473 total xp)_',
'<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
'<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
]
I would like to sort it by the amount of total xp, so the number within the brackets.
You can use the sort callback. Extract the number with a regular expression:
const data = [
'<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
'<@289037609274048513> is level **7,07** _(14473 total xp)_',
'<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
'<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
];
const regex = /(?<=_\()[\d.]+/;
data.sort((a, b) => +a.match(regex) - +b.match(regex));
console.log(data);
The + is used to convert the returned array (with one match element) to a string and then that to a number. You could use ?.[0] to actually get that first array element.
We can try sorting using a custom lambda expression:
var input = [
'<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
'<@289037609274048513> is level **7,07** _(14473 total xp)_',
'<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
'<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
];
var output = input.sort( (a, b) => parseFloat(a.match(/(\d+(?:\.\d+)?) total xp\b/)[1]) - parseFloat(b.match(/(\d+(?:\.\d+)?) total xp\b/)[1]));
console.log(output);
In the above we are extracting the number which is followed by total xp, parsing it as a float, and then using that value in the sorting comparator. If you want descending order, then just reverse the inequality in the lambda function.
Here is another try, looking for a space after the number:
const arr=[
'<@520968882077433856> is level **7,64** _(18115.5 total xp)_',
'<@289037609274048513> is level **7,07** _(14473 total xp)_',
'<@672835870080106509> is level **8,25** _(22473.5 total xp)_',
'<@536686935134175254> is level **6,22** _(10184.5 total xp)_',
];
function getN(s){
return s.match(/_\((.+?) /)[1];
}
arr.sort((a,b)=>getN(a)-getN(b))
console.log(arr)