As far as I understood, I expected them to be printed according to the resolution time of each one (after the callstack is empty), to finally print the setTimeout() message.
However, all solutions are printed when the most time-consuming task is completed. Specifically, it is only when the promise operation of the second call to recursionSecond() is completed that all the others are also printed.
setTimeout(() => console.log('timeout in 0'), 0);
function recursionFirst(number) {
return new Promise((resolve, reject) => {
for(let i = 0; i > (number * (-1)); i--) {
if(i === (number * (-1)) + 1) resolve(i)
}
})
}
function recursionSecond(number) {
return new Promise((resolve, reject) => {
for(let i = 0; i < number; i++) {
if(i === number - 1) resolve(i)
}
})
}
recursionFirst(40)
.then(x => console.log(x))
recursionFirst(400)
.then(x => console.log(x))
recursionFirst(400)
.then(x => console.log(x))
recursionSecond(10)
.then(x => console.log(x))
recursionSecond(2000000000)
.then(x => console.log(x))
recursionSecond(1000)
.then(x => console.log(x))
console.log("Hi!")