If you're using selenium you can use the getText() method so it will perhaps look like driver.findElement(webdriver.By.xpath("XPath")).getText() Altought that's for Java.

For python I believe it looks something like this

value_text = driver.find_element_by_xpath("XPath").text

Can you try below two xpaths

//label[@rel='toltip']/*

you can use regex

import re
a = """<div class="xsmall-12 medium-6 columns">
                        <label class="device-attribute-label" rel="tooltip" title="Proprietary/trade name of the medical device as used in the labeling or catalog.">Brand Name:</label>
                        Snowden-Pencer
                        <br>
                        <label class="device-attribute-label" rel="tooltip" title="Identifies a category or design of devices that have specifications, performance, size, and composition within limits set by the company.">Version or Model:</label>
                        32-0044
                        <br>
                        <label class="device-attribute-label" href="#" rel="tooltip" title="Whether the device is currently offered for sale by the device company. A device no longer in commercial distribution may or may not still be available for purchase in the marketplace.">Commercial Distribution Status:</label>
                        In Commercial Distribution
                        <br>
                        <label class="device-attribute">Catalog Number:</label>
                        32-0044
                        <br>
                        <label class="device-attribute">Company Name:</label>
                        CAREFUSION 2200, INC
                    </div>"""
b = re.findall(r' (.*?)\n', a)
c = [x.lstrip().rstrip() for x in b if '<' not in x and '>' not in x]