I'm trying to solve a problem where you have an array
array = [[a,b,c],[e,f,g],[h,i,j]]
I want to loop through the first letter of the first array, then look at the first of all the other arrays then do a comparison whether they're equal or not. I'm unsure how to do this given that a loop will go through everything in its array. I wrote a nested loop below, but I know it's know it's not the right approach. I basically want something that looks
like
if (array[0][0] == array[1][0] == array[2][0]), then repeat for each element in array[0]
var firstWord = array[0];
var remainderWords = array.slice(1);
for(var i = 0; i < firstWord.length; i++){
for (var j = 0; i< remainderWords.length; j++){
if firstWord[i] == remaindersWord[j][i]
}
Any help would be appreciated.
Use Array.every() to check that a condition is true for all elements of an array.
firstWord.forEach((letter, i) => {
if (remainderWords.every(word => word[i] == letter)) {
// do something
}
});
You can use three nested for or .forEach loops to get to the items in the remainderItems array. Try this
var array = [['a', 'b', 'c'], ['b', 'f', 'g'], ['h', 'c', 'j']];
var firstWord = array[0];
var remainderWords = array.slice(1);
firstWord.forEach((l, idx) => {
remainderWords.forEach(arr => {
arr.forEach(v => {
if (l == v) {
// matched do whatever you want with the variable here
console.log(v)
}
})
})
})