No pude encontrar respuesta para esto en ninguna parte, esta es mi última esperanza. (atrapado en el aprendizaje!!!)
Encuentre el usuario con la mayoría de las habilidades. ¡No tengo ni idea de cómo puedo usar for loop aquí!
Lo intenté -----
x=[] users.getfuction = function(){ x.push(users.Alex.skills.length) x.push(users.Asab.skills.length) x.push(users.Brook.skills.length) x.push(users.Daniel.skills.length) x.push(users.John.skills.length) x.push(users.Paul.skills.length) x.push(users.Thomas.skills.length) max=x[0] for(i=1;i<x.length;i++){ if(x[i]>max){ max=x[i] } } return z } console.log(users.getfuction()) //I dont want to keep pushing the name one by one!! const users = { Alex: { skills: ['HTML', 'CSS', 'JavaScript'] }, Asab: { skills: ['HTML', 'CSS', 'JavaScript', 'Redux', 'MongoDB', 'Express', 'React', 'Node'] }, Brook: { skills: ['HTML', 'CSS', 'JavaScript', 'React', 'Redux'] }, Daniel: { skills: ['HTML', 'CSS', 'JavaScript', 'Python'] }, John: { skills: ['HTML', 'CSS', 'JavaScript', 'React', 'Redux', 'Node.js'] }, Thomas: { skills: ['HTML', 'CSS', 'JavaScript', 'React'] }, Paul: { skills: ['HTML', 'CSS', 'JavaScript', 'MongoDB', 'Express', 'React', 'Node'] } }devuelve una matriz de pares de propiedades [clave, valor] enumerables con clave de cadena enumerables de un objeto determinado.
El pseudocódigo de esto es
loop through each user: if current_user's skill count is greater than the record: set current_user as the best user save current_user's skill count for comparison print out best user [name, {skills}] es una cosa llamada desestructuración . Esto es lo mismo que decir:
for (const entry of Object.entries(users)) { const name = entry[0]; const skills = entry[1].skills; if (skills.length > bestUserSkills) { bestUserName = name; bestUserSkills = skills.length; } } const users = {Alex:{skills:['HTML','CSS','JavaScript']},Asab:{skills:['HTML','CSS','JavaScript','Redux','MongoDB','Express','React','Node']},Brook:{skills:['HTML','CSS','JavaScript','React','Redux']},Daniel:{skills:['HTML','CSS','JavaScript','Python']},John:{skills:['HTML','CSS','JavaScript','React','Redux','Node.js']},Thomas:{skills:['HTML','CSS','JavaScript','React']},Paul:{skills:['HTML','CSS','JavaScript','MongoDB','Express','React','Node']}}; let bestUserName = ""; let bestUserSkills = -1; for (const [name, {skills}] of Object.entries(users)) { if (skills.length > bestUserSkills) { bestUserName = name; bestUserSkills = skills.length; } } console.log(bestUserName); const bestUser = users[bestUserName]; console.log(bestUser);Array.prototype.reduce() se puede usar para ejecutar todos los objetos.
const users = { Alex: { skills: ['HTML', 'CSS', 'JavaScript'] }, Asab: { skills: ['HTML', 'CSS', 'JavaScript', 'Redux', 'MongoDB', 'Express', 'React', 'Node'] }, Brook: { skills: ['HTML', 'CSS', 'JavaScript', 'React', 'Redux'] }, Daniel: { skills: ['HTML', 'CSS', 'JavaScript', 'Python'] }, John: { skills: ['HTML', 'CSS', 'JavaScript', 'React', 'Redux', 'Node.js'] }, Thomas: { skills: ['HTML', 'CSS', 'JavaScript', 'React'] }, Paul: { skills: ['HTML', 'CSS', 'JavaScript', 'MongoDB', 'Express', 'React', 'Node'] } }; let user = Object.keys(users).reduce((prev, name) => { return (users[name].skills.length > users[prev].skills.length) ? name : prev; }); console.log(user); const users = { Alex: { skills: ["HTML", "CSS", "JavaScript"], }, Asab: { skills: [ "HTML", "CSS", "JavaScript", "Redux", "MongoDB", "Express", "React", "Node", ], }, Brook: { skills: ["HTML", "CSS", "JavaScript", "React", "Redux"], }, Daniel: { skills: ["HTML", "CSS", "JavaScript", "Python"], }, John: { skills: ["HTML", "CSS", "JavaScript", "React", "Redux", "Node.js"], }, Thomas: { skills: ["HTML", "CSS", "JavaScript", "React"], }, Paul: { skills: [ "HTML", "CSS", "JavaScript", "MongoDB", "Express", "React", "Node", ], }, }; // method 1, step by step const userSkillMap = Object.keys(users).map((eachUser) => { const skillLength = users[eachUser]["skills"].length; return { [eachUser]: skillLength, }; }); const sortedUsers = userSkillMap.sort((prev, current) => { const prevUserName = Object.keys(prev)[0]; const currentUserName = Object.keys(current)[0]; return current[currentUserName] - prev[prevUserName]; }); const userWithMostSkills = sortedUsers[0]; console.log("map is", userSkillMap); console.log("sortedUsers", sortedUsers); console.log("userWithMostSkills is", userWithMostSkills); // if you wanna chain everything, method 2 const userWithMostSkillsCombine = Object.keys(users) .map((eachUser) => { const skillLength = users[eachUser]["skills"].length; return { [eachUser]: skillLength, }; }) .sort((prev, current) => { const prevUserName = Object.keys(prev)[0]; const currentUserName = Object.keys(current)[0]; return current[currentUserName] - prev[prevUserName]; })[0]; console.log("userWithMostSkillsCombine is", userWithMostSkillsCombine);Espero que te funcione, ¡avísame!