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How to just pick those matching regex which doesn't contains any value behind

Like I have a text

Lorem https://open.spotify.com/episode/0xmdIsJ28Pwix7MOKcK3Zv?si=50957b8039154544 loremhttps://open.spotify.com/episode/0xmdIsJ28Pwix7MOKcK3Zv?si=50957b8039154544lorem

I want my regex to just pick the first occurrence because it's have empty space behind which show sit's independent

Does any body knows how to check that?

Here's my current regex

/(https:\/\/open.spotify.com\/episode\/|spotify:user:spotify:playlist:)([a-zA-Z0-9]+)(.*)/g
about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

If I'm understanding correctly this regex will select just the first occurance:

/(https:\/\/open.spotify.com\/episode\/|spotify:user:spotify:playlist:)([a-zA-Z0-9?=]+)\b/

Note that the regex is not global so the trailing g was removed.

If you want a global regex that only matches when the URL has a space infront of it, you can use:

/\b(https:\/\/open.spotify.com\/episode\/|spotify:user:spotify:playlist:)([a-zA-Z0-9?=]+)/g

where the \b means a word boundry (space, tab, newline).

about 4 years ago · Juan Pablo Isaza Denunciar

0

Remove global g flag at the end of your regex to pick only first entry

about 4 years ago · Juan Pablo Isaza Denunciar

0

You can use the following regex:

/(?<=\s|^)(https:\/\/open.spotify.com\/episode\/|spotify:user:spotify:playlist:)([a-zA-Z0-9]+)(.*?)/g

It allows you to select only the ones having a white space before them or at the beginning of the string.

about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
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