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VistasProblem with filtering javascript multidimensional array of object
I want to filter out data from a multilayered JSON object:
var players = [
0:{
id: "1"
stats:
{
yellow_cards: "0"
saves: "0"
}
explain:
[
0:{
fixture: "251"
stats: [
0:{
identifier: "minutes"
points: "2"
value: "75"
}
]
}
1:{
fixture: "191"
stats:
[
0:{
identifier: "minutes"
points: "2"
value: "83"
}
1:{
identifier: "assists"
points: "3"
value: "1"
}
]
}
]
}
]
I want to sort out the players who have at least one object where identifier = "minutes" and the value is between 50 and 60. If I loop through everything it works fine:
var selected = [];
for(i=0; i<players.length; i++){
for(j=0; j<players[i].explain.length; j++){
for(k=0; k<players[i].explain[j].stats.length;k++){
if(players[i].explain[j].stats[k].identifier == "minutes"){
if(players[i].explain[j].stats[k].value >50 && players[i].explain[j].stats[k].value < 60) {
selected.push(players[i]);
}
}
}
}
}
This takes too much time, and I'm sure there is a more elegant way to do this with array filter and find function. Any help with this is highly appreciated.
Edit: In order to keep it short the array above shows only one object which doesn't fulfill the criteria.
·
Juan Pablo Isaza
1 Respuestas
Responde la pregunta0
Instead of using this tradition for loop for nested filtering, you can achieve the same requirement via Array.filter() along with Array.some()
Here is the performance check with both the approaches : jsbench
Demo :
var players = [{
id: "1",
stats: {
yellow_cards: "0",
saves: "0"
},
explain: [{
fixture: "251",
stats: [{
identifier: "minutes",
points: "2",
value: "75"
}]
}, {
fixture: "191",
stats: [{
identifier: "minutes",
points: "2",
value: "83"
}, {
identifier: "assists",
points: "3",
value: "1"
}]
}]
}];
const selected = players.filter(({ explain }) => {
return explain.some(({ stats }) => {
return stats.some(({ identifier, value }) => {
return identifier === "minutes" && (value > 50 && value < 60)
})
})
})
console.log(selected);
·
Juan Pablo Isaza
Denunciar
Responde la pregunta