I am trying to achieve a check for duplication and push items to array in the below code the functionality works well but instead of using a null is there any other way of doing it
array2.forEach((item) =>
array1.includes(item)
? null
: array1.push(item),
);
You can use && to short circuit the operation
const array1 = [1, 2, 3, 4, 5, 6],
array2 = [4, 5, 6, 7, 8, 9, 10];
array2.forEach((item) => !array1.includes(item) && array1.push(item));
console.log(array1)You can use a set
const set = new Set();
const brr = ["one","one"].forEach(item=> set.add(item));
Array.from(set)
// --> ["one"]
You can use ES6 features like spread operator(...) and Set
let array1 = [1,2,3,4,5,6];
let array2 = [4,5,6,7,8,9,10];
const mergedArrays = [...array1, ...array2];
array1 = [...new Set(mergedArrays)]; // make the array elements unique
console.log(array1);