Empresas
Empleos
  • Sobre nosotros
  • Soluciones
    • Publicación de vacantes
      Publica tu vacante y recibe candidatos calificados en 48h.
    • Evaluación de candidatos
      500+ pruebas técnicas y psicológicas, más anti-fraude.
    • Headhunting
      Búsqueda ejecutiva a la medida de principio a fin.
    • Nómina + EOR
      Dispersión de nómina y EOR en más de 15 países de LATAM.
  • Precios
  • Empleos

0

183
Vistas
How to calcuate item quantiy from array of object if the itemid is same and how to sum up those quantity whose date are same too

I have data in this format

const ChkdArr = [
  {
    date: "2022-05-25",
    itemId: 29,
    quantity: 4,
  },
  {
    date: "2022-05-26",
    itemId: 29,
    quantity: 2,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 7,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 4,
  },
  {
    date: "2022-05-27",
    itemId: 36,
    quantity: 2,
  },
  {
    date: "2022-05-28",
    itemId: 47,
    quantity: 1,
  },
];

i am getting trouble to get a new array with those data whose itemid is same and in those item if the date is same sum up their quantity.

I want the result to look like this i am applying map and filters but my data is repeating and having incorrect results

const DateSortArr = [{
    itemId: 29,
    date: [
      { date: "2022-05-25", quantity: 4 },
      { date: "2022-05-26", quantity: 2 },
    ],
},
  {
    itemId: 36,
    date: [
      { date: "2022-05-25", quantity: 11 },
      { date: "2022-05-27", quantity: 2 },
    ],},
{
    itemId: 47,
    date: [{ date: "2022-05-25", quantity: 1 }],
  },
];
about 4 years ago · Juan Pablo Isaza
3 Respuestas
Responde la pregunta

0

Hello I don't know id undrestand you but you use this fun :

function groupBy(collection, property) {
  var i = 0, val, index,
      values = [], result = [];
  for (; i < collection.length; i++) {
      val = collection[i][property];
      index = values.indexOf(val);
      if (index > -1)
          result[index].push(collection[i]);
      else {
          values.push(val);
          result.push([collection[i]]);
      }
  }
  return result;
}

const ChkdArr = [
  {
    date: "2022-05-25",
    itemId: 29,
    quantity: 4,
  },
  {
    date: "2022-05-26",
    itemId: 29,
    quantity: 2,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 7,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 4,
  },
  {
    date: "2022-05-27",
    itemId: 36,
    quantity: 2,
  },
  {
    date: "2022-05-28",
    itemId: 47,
    quantity: 1,
  },
];
var obj = groupBy(ChkdArr, "date");

console.log(obj)
about 4 years ago · Juan Pablo Isaza Denunciar

0

const ChkdArr = [
  {
    date: "2022-05-25",
    itemId: 29,
    quantity: 4,
  },
  {
    date: "2022-05-26",
    itemId: 29,
    quantity: 2,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 7,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 4,
  },
  {
    date: "2022-05-27",
    itemId: 36,
    quantity: 2,
  },
  {
    date: "2022-05-28",
    itemId: 47,
    quantity: 1,
  },
];

let answer = [];

ChkdArr.map(item =>{
  let id = answer.findIndex(it =>it.itemId === item.itemId);
  if(id === - 1 ){
    answer.push({itemId: item.itemId, data: [{date: item.date, quantity: item.quantity}]})
  }else{
    answer [id] = {itemId: item.itemId, data: [...answer[id].data, {date: item.date, quantity: item.quantity}]}
  }
})

console.log(answer)
about 4 years ago · Juan Pablo Isaza Denunciar

0

This can be done efficiently using a map, and a new output array. In the map, we will store the key as itemId and value as its index in the output array. Then we will loop through the data, and see if the itemId has an index in the map, if it is we will look up that item value from output array, and update the current date value accordingly, otherwise we will create a new object for that item in the array. The below code does just that.

const data = [
  {
    date: "2022-05-25",
    itemId: 29,
    quantity: 4,
  },
  {
    date: "2022-05-26",
    itemId: 29,
    quantity: 2,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 7,
  },
  {
    date: "2022-05-25",
    itemId: 36,
    quantity: 4,
  },
  {
    date: "2022-05-27",
    itemId: 36,
    quantity: 2,
  },
  {
    date: "2022-05-28",
    itemId: 47,
    quantity: 1,
  },
];

let output = [];
let itemIdToIndexMap = {};

data.forEach(item => {
    const itemIndex = itemIdToIndexMap[item.itemId];
    if(itemIndex !== undefined) {
         const itemArray = output[itemIndex];
         const itemWithCurrentDate = itemArray.date.find(newItem => item.date === newItem.date);
         if(itemWithCurrentDate) {
             itemWithCurrentDate.quantity += item.quantity; 
         } else {
             itemArray.date.push({date: item.date, quantity: item.quantity});
         }
    } else {
        output.push({itemId: item.itemId, date: [{date: item.date, quantity: item.quantity}]});
        itemIdToIndexMap[item.itemId] = output.length - 1;
    }
});
console.log(JSON.stringify(output));
about 4 years ago · Juan Pablo Isaza Denunciar
Responde la pregunta
Encuentra empleos remotos

¡Descubre la nueva forma de encontrar empleo!

Top de empleos
Top categorías de empleo
Empresas
Publicar vacante Precios Comercial
Legal
Términos y condiciones Política de privacidad
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomiéndame algunas ofertas
Necesito ayuda